Determine the direction cosines of the line passing through the two points (-2, 3, -4) and (1, 2, 3)?
The problem asks us to determine the direction cosines of a line that passes through two specific points in three-dimensional space: \((-2, 3, -4)\) and \((1, 2, 3)\). Understanding direction cosines is crucial in 3D geometry as they define the orientation of a line with respect to the coordinate axes.
To find the direction cosines, we first need to determine the direction ratios of the line. If a line passes through two points \((x_1, y_1, z_1)\) and \((x_2, y_2, z_2)\), its direction ratios \((a, b, c)\) are given by the differences in their respective coordinates:
Given the points \((-2, 3, -4)\) and \((1, 2, 3)\):
Now, let's calculate the direction ratios:
So, the direction ratios of the line are \((3, -1, 7)\).
Next, we need to find the magnitude (or length) of the vector represented by these direction ratios. If the direction ratios are \((a, b, c)\), the magnitude, denoted as $r$, is calculated using the formula:
$r = \sqrt{a^2 + b^2 + c^2}$
Using our calculated direction ratios \((3, -1, 7)\):
$r = \sqrt{3^2 + (-1)^2 + 7^2}$
$r = \sqrt{9 + 1 + 49}$
$r = \sqrt{59}$
Finally, the direction cosines \((l, m, n)\) are found by dividing each direction ratio by the magnitude. The formulas are:
Substituting the values we found:
Therefore, the direction cosines of the line passing through the points \((-2, 3, -4)\) and \((1, 2, 3)\) are $\left(\frac{3}{\sqrt{59}}, \frac{-1}{\sqrt{59}}, \frac{7}{\sqrt{59}}\right)$.
This matches option 4 provided in the question.
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