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Question

COP of the domestic air conditioner as compared of COP of the domestic refrigerator is

The correct answer is

higher

Understanding COP for Air Conditioners and Refrigerators

The Coefficient of Performance (COP) is a measure of the efficiency of a heat pump, refrigerator, or air conditioning system. It is defined as the ratio of the useful heating or cooling provided to the work required. For a cooling system like a refrigerator or an air conditioner, the useful effect is the heat removed from the cold space.

The formula for COP in cooling mode is:

\( \text{COP} = \frac{\text{Heat Removed from Cold Reservoir}}{\text{Work Input}} \)

or

\( \text{COP} = \frac{Q_L}{W_{in}} \)

where \( Q_L \) is the heat removed from the cold reservoir and \( W_{in} \) is the work input to the system.

Comparing COP of Domestic Air Conditioner and Refrigerator

Both a domestic air conditioner and a domestic refrigerator operate on the principle of a refrigeration cycle, moving heat from a colder space to a warmer space. However, they operate at different temperature ranges:

  • Domestic Refrigerator: A refrigerator cools the inside of a small insulated box (the cold reservoir) to a very low temperature (typically around 4°C for the main compartment and much lower, e.g., -18°C, for the freezer) while rejecting heat to the warmer surroundings (room temperature, e.g., 25°C). The temperature difference between the cold reservoir and the hot reservoir is relatively large, especially for the freezer section.
  • Domestic Air Conditioner: An air conditioner cools the air inside a room (the cold reservoir) to a comfortable temperature (typically around 24-26°C) while rejecting heat to the hotter outside environment (e.g., 35-40°C). The temperature difference between the cold reservoir (room) and the hot reservoir (outside) is typically smaller compared to the temperature difference achieved by a refrigerator cooling to freezer temperatures.

In an ideal refrigeration cycle (like the Carnot cycle), the COP is related to the absolute temperatures of the cold (\( T_L \)) and hot (\( T_H \)) reservoirs:

\( \text{COP}_{\text{Carnot}} = \frac{T_L}{T_H - T_L} \)

From this formula, we can see that for a given hot reservoir temperature \( T_H \), the COP increases as the cold reservoir temperature \( T_L \) increases (or as the temperature difference \( T_H - T_L \) decreases). Conversely, to achieve a lower \( T_L \) (like in a freezer), the temperature difference \( T_H - T_L \) is larger, which results in a lower ideal COP.

While real refrigeration cycles are not as efficient as the Carnot cycle, they follow the same principle regarding temperature difference. Moving heat across a smaller temperature difference requires less work input for the same amount of heat removed. Therefore, an air conditioner, which cools a room to a temperature relatively close to the ambient temperature (smaller \( T_H - T_L \)), generally has a higher COP than a domestic refrigerator, which must cool its interior to much lower temperatures (larger \( T_H - T_L \)).

Thus, the COP of a domestic air conditioner is typically higher compared to the COP of a domestic refrigerator.

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Important Questions from Domestic Air Conditioning

  1. For checking the performance of an AC, one must check ________.

  2. After AC installation, how should one check for the performance?

  3. In a multi split AC system ________

  4. In window type air conditioner, thermostat is fixed between ________.

  5. Where is a Cassette A/C indoor unit installed?

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