The question asks for the ratio of the molar flux of species A in two different diffusion scenarios within a binary mixture of ideal gases (A and B). We are given conditions for Case 1 (diffusion of A through stagnant B) and Case 2 (equimolal counter diffusion of A and B). Fick's first law is applicable.
We need the expressions for the molar flux of A ($N_{A1}$ in Case 1 and $N_{A2}$ in Case 2) relative to a stationary coordinate system.
In this scenario, component B is stagnant ($v_B = 0$). The molar flux of A relative to the stagnant medium is described by:
$N_{A1} = \frac{P_{total} D_{AB}}{P_{B,avg} RT \Delta z} (P_{A1} - P_{A2})$
where $P_{B,avg}$ is the average partial pressure of B across the diffusion path.
Here, the molar fluxes of A and B are equal in magnitude and opposite in direction ($N_A = -N_B$), meaning the total molar flux is zero ($N_{total} = 0$). The molar flux of A is given by:
$N_{A2} = -C_{total} D_{AB} \frac{dx_A}{dz}$
For ideal gases, $C_{total} = P_{total}/(RT)$ and $x_A = P_A/P_{total}$. Assuming a linear partial pressure profile:
$N_{A2} = \frac{D_{AB}}{RT \Delta z} (P_{A1} - P_{A2})$
The required ratio is $\frac{N_{A1}}{N_{A2}}$.
Ratio $= \frac{\frac{P_{total} D_{AB}}{P_{B,avg} RT \Delta z} (P_{A1} - P_{A2})}{\frac{D_{AB}}{RT \Delta z} (P_{A1} - P_{A2})}$
The terms $D_{AB}$, $RT$, $\Delta z$, and $(P_{A1} - P_{A2})$ cancel out, leaving:
Ratio $= \frac{P_{total}}{P_{B,avg}}$
First, find the average partial pressure of A ($P_{A,avg}$):
$P_{A,avg} = \frac{P_{A1} + P_{A2}}{2} = \frac{10 \text{ kPa} + 5 \text{ kPa}}{2} = 7.5 \text{ kPa}$
Next, find the average partial pressure of B ($P_{B,avg}$):
$P_{B,avg} = P_{total} - P_{A,avg} = 100 \text{ kPa} - 7.5 \text{ kPa} = 92.5 \text{ kPa}$
Now, calculate the ratio:
Ratio $= \frac{100 \text{ kPa}}{92.5 \text{ kPa}} \approx 1.08108$
Rounding to two decimal places, the ratio is 1.08.
Consider a non-reactive binary mixture of two ideal gases A and B in an isothermal horizontal closed tube. Due to the concentration difference at the two ends of the tube, equimolal counterdiffusion occurs along the axial direction. No concentration gradients exist in the radial direction. The profile for partial pressure of component A ($p_A$) as a function of axial distance $z$ is shown in the figure. The partial pressure of component B ($p_B$) approaches zero at $z = 0.8 \text{ m}$. At a location $z = z_1$ the partial pressures of the components A and B are equal. The value of $z_1$ (in m) is _____ (rounded off to two decimal places).
