Calculate the V-number for a multimode step-index fiber using the formula and given parameters.
Using the relation $n_2 = n_1 (1 - \Delta)$:
$n_2 = 1.48 \times (1 - 0.01) = 1.48 \times 0.99 = 1.4652$
The V-number formula is $V = \frac{2 \pi a}{\lambda} \sqrt{n_1^2 - n_2^2}$.
Substitute the given and calculated values:
$V = \frac{2 \pi (25 \times 10^{-6} \, \text{m})}{840 \times 10^{-9} \, \text{m}} \sqrt{(1.48)^2 - (1.4652)^2}$
Calculate the difference of squares:
$(1.48)^2 - (1.4652)^2 = 2.1904 - 2.14681504 = 0.04358496$
Calculate the V-number:
$V = \frac{2 \pi \times 25}{840} \times 10^3 \sqrt{0.04358496}$
$V = 0.18700 \times 1000 \times 0.20877$
$V \approx 39.08$
The resulting V-number is approximately 39.
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