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Question

Consider a multimode step-index optical fiber that has a core radius of 25 $\mu$m, a core index of 1.48 and an index difference $\Delta = 0.01$. What is the V-number at an operating wavelength of 840 nm?

The correct answer is
39

V-Number Calculation for Optical Fiber

Calculate the V-number for a multimode step-index fiber using the formula and given parameters.

Given Fiber Parameters:

  • Core radius, $a$ = 25 $\mu$m = $25 \times 10^{-6}$ m
  • Core refractive index, $n_1$ = 1.48
  • Index difference, $\Delta$ = 0.01
  • Operating wavelength, $\lambda$ = 840 nm = $840 \times 10^{-9}$ m

Calculate Cladding Index ($n_2$):

Using the relation $n_2 = n_1 (1 - \Delta)$:

$n_2 = 1.48 \times (1 - 0.01) = 1.48 \times 0.99 = 1.4652$

V-Number Calculation Steps:

The V-number formula is $V = \frac{2 \pi a}{\lambda} \sqrt{n_1^2 - n_2^2}$.

Substitute the given and calculated values:

$V = \frac{2 \pi (25 \times 10^{-6} \, \text{m})}{840 \times 10^{-9} \, \text{m}} \sqrt{(1.48)^2 - (1.4652)^2}$

Calculate the difference of squares:

$(1.48)^2 - (1.4652)^2 = 2.1904 - 2.14681504 = 0.04358496$

Calculate the V-number:

$V = \frac{2 \pi \times 25}{840} \times 10^3 \sqrt{0.04358496}$

$V = 0.18700 \times 1000 \times 0.20877$

$V \approx 39.08$

The resulting V-number is approximately 39.

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Important Questions from Optical Fiber

  1. Fibre optic power meters have input for attaching fiber optic connector and detector:

  2. The material used for making optic-fibre cable in general is-

  3. Multimode step-index fiber with a core diameter of 80 μm and a relative index difference of 1.5% is operating at a wavelength of 0.85 μm. If the core refractive index is 1.48, then the normalized frequency for the fiber is

  4. In a multimode fiber (step index), number of modes passing at an operating wavelength of 1300 nm are 1000, the refractive index of the core is 1.50 and that of the cladding is 1.48. The value of core diameter is:

  5. In optical fibers, the Rayleigh scattering is proportional to:

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