Analyzing the Knock-out Badminton Tournament
This question concerns a single-elimination, or knock-out, badminton tournament. In such tournaments, each game results in one winner and one loser. The loser is eliminated.
Determining Total Games Played
The core principle of a knock-out tournament is that exactly one player is eliminated per game. To determine a single winner from an initial pool of players, all other players must be eliminated.
- Initial number of players, $N = 64$.
- Number of players to be eliminated = $N - 1$.
- Since each game eliminates exactly one player, the total number of games required is equal to the number of players eliminated.
Calculation:
Total games = Number of players - 1
Total games = $64 - 1 = 63$
Therefore, 63 games must be played in total to declare the winner of the tournament.
Important Questions from Numerical Reasoning
A traveller to the town reaches a crossroad. Upon asking residents A, B and C for directions to a certain destination, he gets the following responses
A: turn left
B: do not turn left
C: go straight
If only one among A, B and C is truthful, the traveller
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If x>y>1, which of the following must be true?
(i) In x > In y
(ii) ex > ey
(iii) y2 > x2
(iv) cos x > cos y
