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Consider 35 i.i.d. observations X1, X2, ...., X15 and Y1, Y2, ..., Y20. Let R be the Wilcoxon's rank sum statistic based on the ranks of the X' s in the combined sample. Then the expected value of R is

The correct answer is 270

Wilcoxon Rank Sum Statistic Expected Value

The question asks for the expected value of the Wilcoxon rank sum statistic, denoted as R, based on the ranks of the X observations in a combined sample of X and Y observations.

We are given two independent and identically distributed (i.i.d.) sets of observations:

  • X observations: $X_1, X_2, ..., X_{15}$. The sample size for X is $n_1 = 15$.
  • Y observations: $Y_1, Y_2, ..., Y_{20}$. The sample size for Y is $n_2 = 20$.

The total number of observations in the combined sample is $N = n_1 + n_2 = 15 + 20 = 35$.

The Wilcoxon rank sum statistic R (when calculated as the sum of ranks of the first sample, X in this case) is the sum of the ranks assigned to the $n_1$ observations from the first sample when all $N$ observations from both samples are combined and ranked from 1 to N.

The formula for the expected value of the Wilcoxon rank sum statistic R, based on the sum of ranks of the sample with size $n_1$, is given by:

$$E(R) = \frac{n_1(N + 1)}{2}$$

Where:

  • $n_1$ is the size of the first sample (X).
  • $N$ is the total sample size ($N = n_1 + n_2$).

Calculating the Expected Value

Using the given values:

  • $n_1 = 15$
  • $n_2 = 20$
  • $N = n_1 + n_2 = 15 + 20 = 35$

Substitute these values into the formula for the expected value of R:

$$E(R) = \frac{15(35 + 1)}{2}$$

$$E(R) = \frac{15(36)}{2}$$

$$E(R) = 15 \times \frac{36}{2}$$

$$E(R) = 15 \times 18$$

Now, perform the multiplication:

$$15 \times 18 = 270$$

So, the expected value of the Wilcoxon rank sum statistic R is 270.

This value represents the average sum of ranks one would expect for the X sample if the two populations from which X and Y are drawn are identical (under the null hypothesis).

Comparing this result with the given options, we find that 270 matches Option 1.

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