Comparing Delta Modulation (DM) with PCM system: DM requires A. Lower Sampling Rate B. Higher Sampling Rate C. Large Bandwidth D. Simpler Hardware E. Complex Hardware Choose the correct answer from the options given below:
To compare Delta Modulation (DM) with a Pulse Code Modulation (PCM) system, let's analyze each aspect mentioned in the options:
- Sampling Rate:
- Delta Modulation (DM) requires a higher sampling rate than PCM. This is because DM operates on the principle of approximating the derivative of the input signal. To ensure that the step size in DM accurately tracks the waveform changes, it needs to sample the signal at a much higher rate. Therefore, the option B, "Higher Sampling Rate," is correct.
- Bandwidth:
- The bandwidth required for Delta Modulation is generally larger compared to PCM for the same quality. This is because the higher sampling rate in DM translates to a wider frequency band. Thus, option C, "Large Bandwidth," is correct.
- Hardware Complexity:
- Delta Modulation has simpler hardware requirements compared to PCM. In DM, the signal is represented by a binary sequence of 1's and 0's, making the design simpler and cheaper. The hardware mainly consists of a comparator, integrators, and a digital/analog converter, which are simpler than those required for PCM. Hence, option D, "Simpler Hardware," is correct.
Based on the analysis above, the correct answer is the combination of options B, C, and D. This choice encompasses the requirement for higher sampling rate, larger bandwidth, and simpler hardware that characterize Delta Modulation compared to PCM systems.
Important Questions from Pulse Modulation
Arrange PCM system starting from transmission to reception of signal
A. Sampling and Quantization
B. Quantization and decoding
C. Holding circuit
D. Encoding
E. Low pass filter (LPF)
Choose the correct answer from the options given below:
Consider the following :
(i) Pulse – position – modulation
(ii) Pulse – Code – modulation
(iii) Pulse – Width modulation
(iv) Delta ModulationThe output of which of these in not digital ?
A signal m(t) of bandwidth B=4 kHz it transmitted using a binary companded PCM with µ = 100 and L = 64. The total number of bits for encoding and output SNR are respectively
Which of the following statements are correct ?
(a) PAM can be detected by a band pass filter.
(b) The PWM needs more power than PPM.
(c) Noise can be reduced by increasing sampling rate.
(d) Pulse code modulation is a digital modulation technique.
A channel with bit rate Rb = 36 Kbps is available for PCM voice transmission. Find the sampling rate fs, assuming fm = 3.2 kHz.
