Choose the four digit number, in which the product of the first & fourth digits is 40 and the product of the middle digits is 28. The thousands digit is as much less than the unit digit as the hundreds digit is less than the tens digit.
To find the specific four-digit number, we represent it as $d_1 d_2 d_3 d_4$, where $d_1$ is the thousands digit, $d_2$ the hundreds, $d_3$ the tens, and $d_4$ the units digit.
From $d_1 \times d_4 = 40$, possible pairs of single digits are (5, 8) and (8, 5).
The condition $d_1 < d_4$ means the only valid pair is $(d_1, d_4) = (5, 8)$.
From $d_2 \times d_3 = 28$, possible pairs of single digits are (4, 7) and (7, 4).
The condition $d_2 < d_3$ means the only valid pair is $(d_2, d_3) = (4, 7)$.
Using the determined digits: $d_1=5, d_2=4, d_3=7, d_4=8$. The four-digit number is 5478.
Check if $d_4 - d_1 = d_3 - d_2$.
Since $3 = 3$, the difference condition is satisfied.
The number 5478 meets all the specified criteria.