Chlorine usage in the treatment of 25000 m3/day is 9 kg. The dosage in milligram per litre is:
0.36
Calculating Chlorine Dosage in Water Treatment
This question requires calculating the dosage of chlorine used in treating a specific volume of water. The dosage is typically expressed in milligrams per litre (mg/L). We are given the daily volume of water treated and the mass of chlorine used.
Understanding the Input Data
- Volume of water treated daily: 25000 m³/day
- Chlorine usage: 9 kg
- Target unit for dosage: milligrams per litre (mg/L)
Step-by-Step Calculation
To find the dosage in mg/L, we need to convert the given units (kg and m³) to the required units (mg and L).
1. Convert Chlorine Usage to Milligrams (mg)
We know that 1 kilogram (kg) is equal to 1,000,000 milligrams (mg).
Using LaTeX for the conversion:
$$1 \text{ kg} = 10^6 \text{ mg}$$Therefore, 9 kg of chlorine is:
$$9 \text{ kg} = 9 \times 10^6 \text{ mg} = 9,000,000 \text{ mg}$$2. Convert Water Volume to Litres (L)
We know that 1 cubic meter (m³) is equal to 1000 litres (L).
Using LaTeX for the conversion:
$$1 \text{ m}^3 = 1000 \text{ L}$$So, the total volume of water treated daily is:
$$25000 \text{ m}^3 = 25000 \times 1000 \text{ L} = 25,000,000 \text{ L}$$3. Calculate Chlorine Dosage in mg/L
The dosage is calculated by dividing the mass of the chemical (in mg) by the volume of water treated (in L).
The formula is:
$$ \text{Dosage (mg/L)} = \frac{\text{Mass of Chlorine (mg)}}{\text{Volume of Water (L)}} $$Plugging in the converted values:
$$ \text{Dosage} = \frac{9,000,000 \text{ mg}}{25,000,000 \text{ L}} $$Simplifying the fraction:
$$ \text{Dosage} = \frac{9}{25} \text{ mg/L} $$Calculating the final value:
$$ \text{Dosage} = 0.36 \text{ mg/L} $$Result Comparison with Options
The calculated dosage is 0.36 mg/L. Comparing this with the given options:
- Option 1: 0.0028
- Option 2: 0.36
- Option 3: 360
- Option 4: 2.778
The calculated value matches Option 2.
| Parameter | Given Value | Converted Value | Unit |
|---|---|---|---|
| Volume of Water | 25000 | 25,000,000 | L |
| Chlorine Mass | 9 | 9,000,000 | mg |
| Calculated Dosage | 0.36 | mg/L | |
Important Questions from Disinfection
The dose of chlorination, beyond which any further addition of chlorine will appear as free residual chlorine, is known as:
A city that has a supply of 15000 cubic meters of water per day is treated with a chlorine dosage of 0.5 ppm. For this purpose, the requirement of 25% bleaching powder per day would be.
Which one of the following is used to kill the pathogens?
An experiment shows that a concentration of 0.1 g/m3 of free available chlorine yield a 99% kill of bacteria in 8 minutes. Calculate disinfection rate constant (1 /min)? Assume that Chick's Law and Watson's Law hold with n = 1.
Order 4 disinfectants in increasing order of their disinfection power?
