Calculate the time required to execute the entire instruction cycle if two machine codes, 0011 1110 and 0011 0010, are stored in memory locations 2000H and 2001H, respectively. If the clock frequency is 2 MHz, the first machine code represents opcode to load data byte in the accumulator and the second code represents data to be loaded in the accumulator.
3.5 μs
To accurately determine the time required to execute an entire instruction cycle, we need to understand the components of the instruction, the number of machine cycles and T-states involved, and the system's clock frequency.
The clock frequency is a fundamental parameter that dictates the duration of each clock cycle (T-state).
The clock period (\(T\)), which is the time duration of one T-state, is calculated as the reciprocal of the clock frequency:
\[T = \frac{1}{\text{frequency}}\]
Substituting the given frequency value:
\[T = \frac{1}{2 \times 10^6 \text{ Hz}}\]
\[T = 0.5 \times 10^{-6} \text{ seconds}\]
\[T = 0.5 \text{ μs}\]
So, each T-state lasts for \(0.5\) microseconds.
The problem describes two machine codes stored sequentially in memory:
2000H contains 0011 1110. This is identified as the opcode to load a data byte into the accumulator. In microprocessors like the 8085, this corresponds to an MVI A, data (Move Immediate to Accumulator) instruction.2001H contains 0011 0010. This is the actual data byte that will be loaded into the accumulator.An MVI A, data instruction is a 2-byte instruction. Its execution typically involves two machine cycles in a microprocessor architecture like the 8085:
0011 1110), from memory address 2000H. An Opcode Fetch cycle is crucial for the processor to identify what operation needs to be performed. This cycle typically consumes 4 T-states.0011 0010), from memory address 2001H. This data will be loaded into the accumulator. A Memory Read cycle typically consumes 3 T-states.To find the total number of T-states required for the entire instruction cycle, we sum the T-states of these two machine cycles:
Total T-states = T-states (Opcode Fetch) + T-states (Memory Read)
Total T-states = \(4 \text{ T-states} + 3 \text{ T-states}\)
Total T-states = \(7 \text{ T-states}\)
With the total number of T-states and the clock period determined, we can now calculate the total time required to execute the entire instruction cycle:
Execution Time = Total T-states \(\times\) Clock Period
Execution Time = \(7 \times 0.5 \text{ μs}\)
Execution Time = \(3.5 \text{ μs}\)
Based on the analysis of the instruction (MVI A, data) and the given clock frequency, the time required to execute the entire instruction cycle is \(3.5 \text{ μs}\).
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