Calculate the length (m) of tangent of a 5-degree curve, if the deflection angle is 60 degree.
198.6
This question asks us to determine the length of the tangent for a circular curve, given its degree and the total deflection angle.
Here's what we are given:
We need to calculate the Tangent Length (T) of the curve.
To find the tangent length, we first need to calculate the radius (R) of the curve using the given degree of curve (D).
Step 1: Calculate the Radius (R)
Using the relationship \(R = \frac{1718.9}{D}\), where R will be in meters:
\[ R = \frac{1718.9}{5^{\circ}} \]
\[ R = 343.78 \text{ m} \]
So, the radius of the 5-degree curve is approximately 343.78 meters.
Step 2: Calculate the Tangent Length (T)
The tangent length (T) of a simple circular curve is calculated using the formula:
\[ T = R \tan\left(\frac{\Delta}{2}\right) \]
We have the radius \(R = 343.78\) m and the deflection angle \(\Delta = 60^{\circ}\). The half deflection angle is \(\frac{\Delta}{2} = \frac{60^{\circ}}{2} = 30^{\circ}\).
Now, plug these values into the formula:
\[ T = 343.78 \times \tan(30^{\circ}) \]
The value of \(\tan(30^{\circ})\) is approximately 0.57735.
\[ T \approx 343.78 \times 0.57735 \]
\[ T \approx 198.59 \text{ m} \]
Rounding to one decimal place, the tangent length is approximately 198.6 m.
This calculated value matches one of the given options.
| Parameter | Symbol | Value |
|---|---|---|
| Degree of Curve | D | \(5^{\circ}\) |
| Deflection Angle | \(\Delta\) | \(60^{\circ}\) |
| Calculated Radius | R | \(343.78\) m |
| Calculated Tangent Length | T | \(198.59\) m |
The calculated tangent length is approximately 198.6 meters.
| Element | Symbol | Formula | Description |
|---|---|---|---|
| Radius | R | Varies with definition of D (e.g., \(R=\frac{1718.9}{D}\) m) | Radius of the circular arc |
| Tangent Length | T | \(R \tan(\Delta/2)\) | Distance from Tangent Point to Point of Intersection |
| Length of Curve | L | \(R \Delta \frac{\pi}{180}\) (Δ in degrees) or \(R \Delta\) (Δ in radians) | Length along the arc from BC to EC |
| Long Chord | LC | \(2R \sin(\Delta/2)\) | Straight line distance from BC to EC |
| External Distance | E | \(R(\sec(\Delta/2) - 1)\) or \(R(\frac{1}{\cos(\Delta/2)} - 1)\) | Distance from the Point of Intersection to the midpoint of the curve |
| Mid-ordinate | M | \(R(1 - \cos(\Delta/2))\) | Distance from the midpoint of the long chord to the midpoint of the curve |
Where BC is Beginning of Curve, EC is End of Curve, and PI is Point of Intersection.
The term "degree of curve" has different definitions, which can affect the calculation of the radius (R). It's important to know which definition is being used in a particular context.
The problem implicitly used the arc definition relating D to R via \(R \approx \frac{1718.9}{D}\) meters to arrive at the given options.
The radius of a simple circular curve is 300m and the length of its specified chord is 20 m, The degree of the curve is:
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A curve which consists of two circular arcs of same and different radii having their centres to the different sides of the common tangent is called:
The tangent length for a simple curve is 10 m. the chainage of point of intersection is 344.465 m. The chainage of starting point of curve is:
In India, the standard chord length used in curves is: