$C$ is the third proportional of 44 and $B$. If $B$ is the sum of the first three even natural numbers, then find the value of $C$.
(Round off your answer to two decimal places)
To find the value of C, we first need to determine the value of B. The problem states that B is the sum of the first three even natural numbers.
The first three even natural numbers are 2, 4, and 6.
Therefore, the value of B is:
B = 2 + 4 + 6
B = 12
The problem states that C is the third proportional of 44 and B. This means that the ratio between the first number (44) and the second number (B) is the same as the ratio between the second number (B) and the third number (C).
Mathematically, this can be represented as:
$$ \frac{44}{B} = \frac{B}{C} $$
We can rearrange the formula to solve for C:
$$ C = \frac{B \times B}{44} $$
Now, substitute the value of B which we found to be 12:
$$ C = \frac{12 \times 12}{44} $$
$$ C = \frac{144}{44} $$
To find the numerical value of C, we divide 144 by 44:
$$ C \approx 3.272727... $$
The question asks to round the answer to two decimal places.
Rounding 3.272727... to two decimal places gives us 3.27.
The calculated value of C is approximately 3.27, which matches one of the given options.
Find the third proportional to 6 and 12.
If p is the third proportional to 3, 9, then what is the fourth proportional to 6, p, 4?
What is the third proportional to 10 and 25?
What is the third proportional to 10 and 20?
The third proportional to (x2 - y2) and (x - y) is: