All Exams Test series for 1 year @ ₹349 only
Question

Burning of 1 mol of $\text{CH}_4$ liberates 890 kJ of energy and 1 mol of $\text{CO}_2$. Since 1 mol of $\text{CO}_2$ has 12 g of carbon, the higher heating value (HHV) of methane is :

The correct answer is
13.5 gC/MJ

Understanding Methane's Higher Heating Value (HHV)

The Higher Heating Value (HHV) represents the total amount of heat released when a fuel is burned completely, assuming the water produced is condensed back into liquid. We need to find the HHV of methane ($\text{CH}_4$) in terms of grams of carbon (gC) per megajoule (MJ) of energy released.

Calculation Steps

  1. Identify Given Information:
    • Combustion of 1 mol of $\text{CH}_4$ releases 890 kJ of energy.
    • Combustion of 1 mol of $\text{CH}_4$ produces 1 mol of $\text{CO}_2$.
    • 1 mol of $\text{CO}_2$ contains 12 g of carbon (C).
  2. Relate Energy to Carbon Content:

    The combustion of 1 mol of $\text{CH}_4$ releases 890 kJ and corresponds to 12 g of carbon.

  3. Convert Energy Units:

    Convert the energy from kilojoules (kJ) to megajoules (MJ), knowing that 1 MJ = 1000 kJ.

    Energy = $890 \text{ kJ} \times \frac{1 \text{ MJ}}{1000 \text{ kJ}} = 0.890 \text{ MJ}$

  4. Calculate HHV in gC/MJ:

    Divide the mass of carbon associated with the combustion by the energy released in MJ.

    HHV = $\frac{\text{Mass of Carbon}}{\text{Energy Released}} = \frac{12 \text{ gC}}{0.890 \text{ MJ}}$

    HHV $\approx 13.483 \text{ gC/MJ}$

  5. Round the Result:

    Rounding the result to one decimal place gives 13.5 gC/MJ.

Final HHV Value

The higher heating value (HHV) of methane is approximately 13.5 gC/MJ.

Was this answer helpful?

Important Questions from Energy and Environment - Teaching

  1. Which of the following fuels has the highest HHV carbon intensity ?
  2. The air-to-fuel ratio (A/F) for complete combustion in an internal combustion engine is about :
  3. Consider solar insolation of $400 \text{ W/m}^2$ incident on a single solar cell of area $100 \text{ cm}^2$. If only $15\%$ of the photons cause electron - hole pairs and the average energy of incident photons is $\sim 1 \text{ eV}$, the short circuit current of the cell is :
  4. In terms of the calorific value, identify the correct sequence :
  5. At a given location the wind speeds are predominantly in the range $6$ to $6.4 \text{ m/s}$. This location’s wind power class will be termed as :
Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App