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Question

Body A having a mass of 2 kg and body B having a mass of 3 kg moving towards each other with velocities 4 m/s and 2 m/s, respectively, will collide and ______ in an elastic collision.

The correct answer is

move in opposite direction

Concept:

Collisions are generally classified into two types: elastic and inelastic collisions.

This classification is based on the law of conservation, and the laws of collision state:

  • Momentum is conserved in all collisions.
  • Kinetic energy is also conserved in elastic collisions.
  • In an inelastic collision, kinetic energy is not conserved. In a perfectly inelastic collision, the objects stick together after the collision.

Perfectly elastic collision

If the laws of momentum conservation and kinetic energy hold well during the collision.

That is, initial velocity = final velocity

Inelastic collision

If the law of momentum conservation holds well during the collision while kinetic energy does not.

However, inelastic collisions follow the law of conservation of linear momentum.

Coefficient of restitution (e)

\(e = \frac{{Relative\;velocity\;after\;collision}}{{Relative\;velocity\;before\;collision}} = \frac{{{v_2} - {v_1}}}{{{u_1} - {u_2}}}\)

  • For a perfectly elastic collision, e = 1
  • For an inelastic collision, e <1
  • For a perfectly inelastic collision, e = 0

 

Calculation:

Let us assume that,

Mass of body A, mA = 2 kg

Block A, uA = 4 m/s . velocity

Mass of body B, mB = 3 kg

Velocity of block B, uB = -2 m/s

Now, according to the law of conservation of momentum

mA uA + mB uB = mA vA + mB vB

2 x 4 - 3 x (-2) = 2 x vA + 3 x vB

2 x vA + 3 x vB = 2      -----(1)

Now, for an inelastic collision, the coefficient of restitution is always one and can be expressed as

\(e=1=\frac{{{v}_{B}}-{{v}_{A}}}{{{u}_{A}}-{{u}_{B}}}=\frac{{{v}_{B}}-{{v}_{A}}}{4+2}\Rightarrow {{v}_{B}}-{{v}_{A}}=6\)     ------(2)

Thus, comparing both quadratic equations, we obtain the values of the velocities of bodies A and B as follows

\({{v}_{B}}=\frac{14}{5}m/s\)

And now substituting this value into eq (2), we get, \({{v}_{A}}=-\frac{16}{5}m/s\)

Thus, we can see that body A will be moving in the opposite direction compared to body B.

Therefore, in this case, body A and body B will move in opposite directions in an elastic collision.

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Important Questions from Motion

  1. The motion of a particle of mass m is described by the relation, y = ut - 1⁄2 gt2, where u is the initial velocity of the particle. The force acting on the particle is

  2. The motion of ______ body is an example of uniformly accelerated motion.

  3. in a particular direction is velocity.
  4. Motion of an object is if its velocity is constant.

  5. The motion of the body moving along a circular path is an example of ______.

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