Benzaldehyde reacts with PCl5 to give
Benzal chloride
The reaction between benzaldehyde and phosphorus pentachloride ($\text{PCl}_5$) is a common transformation in organic chemistry. Aldehydes and ketones react with phosphorus pentachloride where the carbonyl oxygen atom ($\text{=O}$) is replaced by two chlorine atoms ($\text{-Cl}$).
When benzaldehyde reacts with $\text{PCl}_5$, the oxygen atom in the carbonyl group ($\text{=O}$) of benzaldehyde is substituted by two chlorine atoms. The general reaction for a carbonyl compound ($\text{R}_2\text{C=O}$) with $\text{PCl}_5$ is:
\(\text{R}_2\text{C=O} + \text{PCl}_5 \rightarrow \text{R}_2\text{CCl}_2 + \text{POCl}_3\)
In the case of benzaldehyde, $\text{R}$ represents the phenyl group ($\text{C}_6\text{H}_5$) and a hydrogen atom ($\text{H}$). So the reaction is:
\(\text{C}_6\text{H}_5\text{CHO} + \text{PCl}_5 \rightarrow \text{C}_6\text{H}_5\text{CHCl}_2 + \text{POCl}_3\)
The main product formed is $\text{C}_6\text{H}_5\text{CHCl}_2$, which is called benzal chloride or benzylidene chloride. Phosphorus oxychloride ($\text{POCl}_3$) is a byproduct.
Let's look at the structure of the product, $\text{C}_6\text{H}_5\text{CHCl}_2$. It has a benzene ring attached to a carbon atom that is bonded to one hydrogen atom and two chlorine atoms. This structure corresponds to benzal chloride.
Let's consider why the other options are incorrect:
Therefore, when benzaldehyde reacts with $\text{PCl}_5$, the expected product is benzal chloride.
The reaction between benzaldehyde and phosphorus pentachloride is a specific example of how $\text{PCl}_5$ acts as a chlorinating agent to replace the carbonyl oxygen.
In summary, the reaction of benzaldehyde with $\text{PCl}_5$ yields benzal chloride as the primary organic product.
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1. Carbon forms the basis for all living organisms and many things we use
2. Carbon shows tetra-valency and the property of catenation
3. Carbon forms covalent bonds with itself and other elements
4. Carbon forms compounds containing triple and tetra bonds between carbon atoms
Select the correct answer using the code given below:
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