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Question

Based on the comparison of a hollow shaft with a solid shaft for the same weight following statements are made

I. Natural frequency of hollow shaft is higher than that of the solid shaft. 

II. Stiffness of a hollow shaft is more than that of a solid shaft.

III. The diameter of a hollow shaft is greater than that of a solid shaft for same torque transmission.

IV. Hollow shaft is manufactured by extrusion process.

Choose the best statements from above which signify the advantages of hollow shaft over a solid shaft and answer below:

The correct answer is

Statements I and II only

Hollow vs Solid Shaft Comparison for Equal Weight

This analysis compares the properties of hollow shafts and solid shafts when they are manufactured to have the same total weight. We evaluate several statements to identify the advantages offered by hollow shafts in mechanical design.

Natural Frequency Advantage of Hollow Shafts

The natural frequency ($f_n$) of a shaft represents its fundamental frequency of vibration when disturbed. It is calculated using the formula:

$$f_n = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$$

Here, '$k$' represents the stiffness of the shaft, and '$m$' is its mass. For a hollow shaft compared to a solid shaft of identical weight (meaning $m$ is constant), the hollow shaft generally exhibits greater stiffness ($k$). This is due to its material distribution; the material is placed farther from the central axis, increasing resistance to bending and torsion. Consequently, with a higher stiffness ($k$) and the same mass ($m$), the hollow shaft achieves a higher natural frequency ($f_n$).

Advantage: A higher natural frequency is beneficial as it shifts the shaft's resonant frequencies to higher operating speeds. This reduces the likelihood of encountering resonance during typical use, thereby enhancing safety and reliability.

Stiffness Advantage of Hollow Shafts

Stiffness measures a component's resistance to deformation under applied forces. For shafts, torsional stiffness (resistance to twisting) is crucial. Torsional stiffness depends significantly on the shaft's polar moment of inertia ($J$) and the material's shear modulus ($G$). The relationship is often expressed as $GJ$, where $G$ is the shear modulus.

When considering shafts manufactured for the same weight, a hollow shaft design inherently provides a larger polar moment of inertia ($J$) than a solid shaft. Maximizing the distance of the material from the rotational axis enhances $J$. A greater polar moment of inertia ($J$) directly translates to higher torsional stiffness ($GJ$).

Advantage: Enhanced stiffness means the shaft undergoes less angular twist under a given torque. This leads to more precise power transmission and improved performance in machinery.

Diameter vs Torque Transmission Comparison

Statement III posits that a hollow shaft's diameter exceeds that of a solid shaft when transmitting the same torque. It is true that for a given weight, a hollow shaft typically has a larger outer diameter than a comparable solid shaft. This larger diameter, coupled with a higher polar moment of inertia ($J$), generally allows the hollow shaft to transmit more torque effectively for a given maximum stress level. However, this statement focuses on a specific condition ('for same torque transmission') and diameter comparison, which might not capture the fundamental performance advantages as directly as statements regarding stiffness and frequency.

Hollow Shaft Manufacturing Process

Statement IV suggests that hollow shafts are typically manufactured via extrusion. While extrusion is a viable method for producing hollow profiles, it's not the sole manufacturing technique. Hollow shafts can also be produced by machining (drilling) solid bars, forging, or casting. Therefore, mentioning extrusion does not represent a unique or universal advantage of hollow shafts compared to solid shafts.

Key Advantages Identified

In summary, the primary advantages of using hollow shafts over solid shafts, particularly when manufactured to the same weight, are their improved stiffness and higher natural frequency. Statements I and II correctly identify these significant benefits in mechanical design and performance.

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Important Questions from Torsional Vibration

  1. Torsional vibrations on a crankshaft is reduced by ______.
  2. A shaft which is 50 mm diameter and 3 metres long is simply supported at the ends and carries three loads of 1000 N, 1500 N and 750 N at 1 m, 2 m and 2.5 m from the left support. The Young's modulus for shaft material is 200 \(\rm \frac{GN}{m^2}\). Determine the frequency of transverse vibration.

  3. Consider a uniform shaft of length L fixed at its upper end and carrying a disc of the moment of inertia I at its lower end. The disc is twisted about the vertical axis and released. 'fa' is the natural frequency of the system when the shaft is assumed as massless, and 'fb' is the natural frequency of the system when the shaft is considered of the same moment of inertia as that of the disc. Find the ratio fa/fb.

  4. A rod of mass 'M' and length '2L' is suspended at its middle by a wire. It exhibits torsional oscillations; if two masses each of 'm' are attached at distance 'L/2' from its centre of both sides, it reduces the oscillation frequency by 10%. The value of the ratio M/m is close to :
  5. A solid steel shaft transmits 40 kW of power at a speed of \(\frac{75}{\pi}\)Hz. The internal torque needed in the shaft is

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