Based on the alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group?
(Note: The odd man out is not based on the number of consonants/vowels or their position in the letter cluster.)

Question

Prepp Team · Accepted Answer

Identifying the Odd Letter Group

The question requires finding the letter group that does not follow the same alphabetical relationship pattern as the others. We need to analyze the alphabetical positions of the letters in each option.

Alphabetical Position Analysis

First, let's determine the standard alphabetical position for each letter:

A=1, B=2, C=3, ..., Z=26

Now, let's examine the differences between the positions of adjacent letters in each option:

Option 1: MIL

M is the 13th letter.
I is the 9th letter.
L is the 12th letter.
Difference between M and I: $|13 - 9| = 4$
Difference between I and L: $|9 - 12| = 3$
Pattern: Differences are 4 and 3.

Option 2: QMO

Q is the 17th letter.
M is the 13th letter.
O is the 15th letter.
Difference between Q and M: $|17 - 13| = 4$
Difference between M and O: $|13 - 15| = 2$
Pattern: Differences are 4 and 2.

Option 3: SOQ

S is the 19th letter.
O is the 15th letter.
Q is the 17th letter.
Difference between S and O: $|19 - 15| = 4$
Difference between O and Q: $|15 - 17| = 2$
Pattern: Differences are 4 and 2.

Option 4: OKM

O is the 15th letter.
K is the 11th letter.
M is the 13th letter.
Difference between O and K: $|15 - 11| = 4$
Difference between K and M: $|11 - 13| = 2$
Pattern: Differences are 4 and 2.

Conclusion

Three options (QMO, SOQ, OKM) share a common pattern where the absolute difference between the first and second letters is 4, and the absolute difference between the second and third letters is 2.

Option MIL (MIL) has differences of 4 and 3. Since this pattern differs from the other three, MIL is the odd one out.