drives 7 km, turns right and drives 9 km. He then takes a right turn and drives 7 km. He
takes a final right turn, drives 5 km and stops at Point P. How far (shortest distance) and
towards which direction should he drive in order to reach Point A again? (All turns are
$90^{\circ}$ turns only unless specified.)
This problem involves tracking a person's movement based on directions and distances to determine the final position relative to the starting point. We need to calculate the shortest distance and the required direction to return to the origin.
Let's track Babar's position using a coordinate system, assuming Point A is the origin (0, 0). We'll consider West as the negative x-direction, East as the positive x-direction, North as the positive y-direction, and South as the negative y-direction.
Babar's starting point, A, is at coordinates (0, 0). His final stopping point, P, is at coordinates (-18, 0).
To find the shortest distance between P and A, we calculate the difference in their coordinates.
The net displacement is 18 km along the x-axis. Since Point P has an x-coordinate of -18 and Point A has an x-coordinate of 0, Point P is located 18 km to the West of Point A.
Therefore, to drive from Point P back to Point A, Babar needs to travel 18 km in the opposite direction of West, which is East.
| Leg | Direction | Distance (km) | Change in X | Change in Y | Coordinates |
|---|---|---|---|---|---|
| Start | - | - | 0 | 0 | (0, 0) (Point A) |
| 1 | West | 14 | -14 | 0 | (-14, 0) |
| 2 | South | 7 | 0 | -7 | (-14, -7) |
| 3 | West | 9 | -9 | 0 | (-23, -7) |
| 4 | North | 7 | 0 | +7 | (-23, 0) |
| 5 | East | 5 | +5 | 0 | (-18, 0) (Point P) |