Average price of 20 pens is Rs. 18. If 12 new pens are added, then the average price rise by Rs. 4. What is the total price of the new pens?
Rs. 344
The problem asks us to find the total price of 12 new pens added to a group of 20 pens, given the initial average price and the new average price after the addition.
The average price is calculated by dividing the total price of items by the number of items. Mathematically, this is:
$$\text{Average Price} = \frac{\text{Total Price}}{\text{Number of Items}}$$
From this formula, we can also find the total price if we know the average price and the number of items:
$$\text{Total Price} = \text{Average Price} \times \text{Number of Items}$$
We are given that the average price of 20 pens is Rs. 18.
Using the formula for total price:
$$\text{Initial Total Price} = \text{Initial Average Price} \times \text{Number of Initial Pens}$$
$$\text{Initial Total Price} = 18 \times 20 = \text{Rs. } 360$$
So, the total price of the initial 20 pens was Rs. 360.
When 12 new pens are added:
The average price rises by Rs. 4. The initial average price was Rs. 18.
Now we have the total number of pens and the new average price:
Using the formula for total price with the new values:
$$\text{New Total Price} = \text{New Average Price} \times \text{Total Number of Pens}$$
$$\text{New Total Price} = 22 \times 32$$
Let's calculate $22 \times 32$:
$$22 \times 32 = 22 \times (30 + 2) = (22 \times 30) + (22 \times 2) = 660 + 44 = 704$$
So, the new total price of the 32 pens is Rs. 704.
The new total price is the sum of the initial total price and the total price of the new pens.
$$\text{New Total Price} = \text{Initial Total Price} + \text{Total Price of New Pens}$$
We want to find the Total Price of New Pens:
$$\text{Total Price of New Pens} = \text{New Total Price} - \text{Initial Total Price}$$
$$\text{Total Price of New Pens} = 704 - 360 = \text{Rs. } 344$$
Therefore, the total price of the 12 new pens is Rs. 344.
| Item | Number | Average Price (Rs.) | Total Price (Rs.) |
|---|---|---|---|
| Initial Pens | 20 | 18 | $$20 \times 18 = 360$$ |
| New Pens | 12 | ? | ? |
| Total Pens (After Addition) | $$20 + 12 = 32$$ | $$18 + 4 = 22$$ | $$32 \times 22 = 704$$ |
From the table and calculations, the total price of the new pens is the difference between the final total price and the initial total price: $$704 - 360 = 344$$.
| Concept | Formula | Explanation |
|---|---|---|
| Average | $$\text{Average} = \frac{\text{Sum of Quantities}}{\text{Number of Quantities}}$$ | A measure of the central value of a set of numbers. |
| Total Sum | $$\text{Total Sum} = \text{Average} \times \text{Number of Quantities}$$ | The sum of all values in the set. |
| Change in Average | Affects the Total Sum | Adding items with a different average value changes the overall average and total sum. |
When tackling average problems involving adding or removing items, the key is to always work with the total sum (or total price in this case). The average is just a derived value.
In this specific problem, the average price increased, which means the new pens added were, on average, more expensive than the initial pens. If the average had decreased, the new pens would have been, on average, less expensive.
The final answer is Rs. 344.
A dealer sold an article at a loss of 2%. Had he sold it for Rs. 44 more, he would have gained 20%. Find the cost price of the article
Radha purchased a Computer table for Rs. 10000 and a Centre table for Rs. 5000. She sold Computer table with 8% profit. With what profit percent should she sell the Centre table so as to gain 10% on the whole transaction.
If selling price of 75 articles is equal to cost price of 60 articles, then the approximate loss or gain percent is :
A.T.V. is sold at 8% gain. Had it been sold for Rs.2553 less; there would have been loss of 15%. To gain 18%, the selling price (in Rs.) of T.V. would be:
Some fruits are bought at 15 for Rs. 140 and an equal number of fruits at 10 for Rs. 120. If all the fruits are sold at Rs. 132 per dozen, then what is the profit percent in the entire transaction?