This problem involves calculating the annual rate of interest when interest is compounded half-yearly.
The formula for compound interest is:
$$ A = P \left(1 + \frac{r}{n}\right)^{nt} $$
Where:
In this case, the interest is compounded half-yearly. This means:
The formula becomes:
$$ A = P \left(1 + \frac{r/2}{100}\right)^{3} $$
Or simplified:
$$ A = P \left(1 + \frac{r}{200}\right)^{3} $$
We are given:
Substitute these values into the formula:
$$ 19,683 = 15,625 \left(1 + \frac{r}{200}\right)^{3} $$
Divide both sides by the principal amount (₹15,625):
$$ \frac{19,683}{15,625} = \left(1 + \frac{r}{200}\right)^{3} $$
To solve for the term inside the parenthesis, we need to find the cube root of both sides:
$$ \sqrt[3]{\frac{19,683}{15,625}} = 1 + \frac{r}{200} $$
We need to find the cube roots of 19,683 and 15,625.
Let's check potential cubes:
So, the cube root is:
$$ \frac{27}{25} = 1 + \frac{r}{200} $$
Now, isolate the rate ($r$):
$$ \frac{r}{200} = \frac{27}{25} - 1 $$
Find a common denominator:
$$ \frac{r}{200} = \frac{27}{25} - \frac{25}{25} $$
$$ \frac{r}{200} = \frac{2}{25} $$
Multiply both sides by 200:
$$ r = \frac{2}{25} \times 200 $$
$$ r = 2 \times \frac{200}{25} $$
$$ r = 2 \times 8 $$
$$ r = 16 $$
The annual rate of interest ($r$) is 16%.
At what rate percent per annum will Rs. 7200 amount to Rs. 7938 in one year, if interest is compounded half yearly?
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What is the difference (in Rs.) between the interests on Rs. 50,000 for one year at 8% per annum compounded half yearly and yearly?
A sum of money becomes Rs. 11,880 after 4 years and Rs. 17,820 after 6 years on compound interest, if the interest is compounded annually. What is the half of the sum (in Rs.)?
A sum invested at compound interest amounts to Rs. 7,800 in 3 years and Rs. 11,232 in 5 years. What is the rate per cent?