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Question

At a temperature of 47°C the thermal voltage is (Given value of Boltzmann's constant = $1.38 \times 10^{-23}$ joule/°K):

The correct answer is
27.6 mV

Understanding Thermal Voltage Calculation

The question asks us to find the thermal voltage at a specific temperature. The thermal voltage ($V_T$) is a concept often used in semiconductor physics and electronics. It represents the voltage equivalent of thermal energy ($kT$) per charge carrier ($q$).

Key Formula for Thermal Voltage

The formula to calculate thermal voltage is:

$ V_T = \frac{k_B T}{q} $

Where:

  • $V_T$ is the thermal voltage.
  • $k_B$ is the Boltzmann's constant, given as $1.38 \times 10^{-23}$ J/K.
  • $T$ is the absolute temperature in Kelvin (K).
  • $q$ is the elementary charge, which is approximately $1.602 \times 10^{-19}$ Coulombs (C).

Step 1: Convert Temperature to Kelvin

The temperature is given in Celsius (°C), but the formula requires the temperature in Kelvin (K). The conversion formula is:

$ T(\text{K}) = T(\text{°C}) + 273.15 $

Given the temperature is 47°C:

$ T = 47 + 273.15 = 320.15 \text{ K} $

Step 2: Calculate Thermal Voltage

Now, substitute the values into the thermal voltage formula:

$ V_T = \frac{(1.38 \times 10^{-23} \text{ J/K}) \times (320.15 \text{ K})}{1.602 \times 10^{-19} \text{ C}} $

First, calculate the numerator:

$ k_B T = (1.38 \times 10^{-23}) \times 320.15 \approx 4.41807 \times 10^{-21} \text{ J} $

Now, divide by the elementary charge ($q$):

$ V_T = \frac{4.41807 \times 10^{-21} \text{ J}}{1.602 \times 10^{-19} \text{ C}} $

Performing the division:

$ V_T \approx 0.02758 \text{ V} $

Step 3: Convert Result to Millivolts (mV)

The options are given in millivolts (mV). To convert Volts (V) to millivolts (mV), multiply by 1000:

$ V_T (\text{mV}) = 0.02758 \text{ V} \times 1000 \text{ mV/V} $ $ V_T \approx 27.58 \text{ mV} $

Rounding the result to one decimal place gives 27.6 mV.

Step 4: Compare with Options

Let's compare our calculated result with the given options:

  • Option 1: 27.6 mV
  • Option 2: 27.6 V
  • Option 3: 27.6 $ \mu V $
  • Option 4: 2.76 V

Our calculated value of approximately 27.6 mV matches Option 1.

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Important Questions from Miscellaneous

  1. Which of the following relationships is/are not true?
    (A). Most probable velocity = $\sqrt{\frac{2RT}{M}}$
    (B). PV = $\frac{3}{2}kT$
    (C). Compressibility factor Z = $\frac{pV}{nRT}$
    (D). Average kinetic energy of gas = $\frac{1}{2}kT$
    Choose the correct answer from the options given below
  2. Match List-I with List-II
    List-IList-II
    Electronic ConfigurationFirst Ionisation energy (kJ mol$^{-1}$)
    (A). ns$^2$(I). 2100
    (B). ns$^2$np$^1$(II). 1400
    (C). ns$^2$np$^3$(III). 800
    (D). ns$^2$np$^6$(IV). 900

    Choose the correct answer from the options given below:
  3. The shielding constant of a 2p electron (calculated using Slater's rules) is
  4. Match List-I with List-II
    List-IList-II
    SpectroscopyProperty
    (A). Raman(I). Polarizability
    (B). FTIR(II). Dipole Moment
    (C). UV-Visible(III). Absorbance
    (D). NMR(IV). Spin

    Choose the correct answer from the options given below:
  5. The structure of protein comprises of:
    (A). Primary structure of protein is associated with amino acids
    (B). Secondary structure of protein is associated to peptides
    (C). Tertiary structure of protein is associated with polypeptide chains
    (D). Quaternary structure of protein is associated with polypeptide chains
    Choose the correct answer from the options given below:
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