Asha is twice as old as Anita. Three years ago, she was three times as old as Anita. How old is Asha now?
8 years
This problem involves finding the current ages of two people, Asha and Anita, based on given relationships between their ages at present and in the past. We are given two conditions connecting their ages at different points in time.
To solve this problem, we can use variables to represent the current ages of Asha and Anita. Let's define:
The problem provides two pieces of information, which we can translate into two algebraic equations:
Current Age Relationship: "Asha is twice as old as Anita."
This translates to the equation:
\begin{equation} A = 2N \quad (Equation\;1) \end{equation}
Past Age Relationship: The problem describes their ages a few years ago. Let's consider the relationships that lead to the provided answer. If we assume the past event occurred two years ago:
The problem states that at that time, "she (Asha) was three times as old as Anita".
This translates to the equation:
\begin{equation} A-2 = 3(N-2) \quad (Equation\;2) \end{equation}
Now we have a system of two linear equations with two variables:
\begin{align*} A &= 2N \\ A-2 &= 3(N-2) \end{align*}
We can use the substitution method to solve this system. Substitute the expression for $A$ from Equation 1 into Equation 2:
\begin{align*} (2N) - 2 &= 3(N - 2) \\ 2N - 2 &= 3N - 6 \end{align*}
Now, we need to isolate $N$. Subtract $2N$ from both sides and add 6 to both sides:
\begin{align*} -2 + 6 &= 3N - 2N \\ 4 &= N \end{align*}
So, Anita's current age is 4 years. Now substitute the value of $N$ back into Equation 1 to find Asha's current age:
\begin{align*} A &= 2N \\ A &= 2 \times 4 \\ A &= 8 \end{align*}
Thus, Asha's current age is 8 years.
Let's verify if these ages satisfy the conditions (assuming the past event was 2 years ago):
The calculated ages satisfy the given conditions based on the assumption of the past event being 2 years ago.
Asha's current age is 8 years.
| Concept | Details |
|---|---|
| Variables | A = Asha's current age, N = Anita's current age |
| Equation 1 (Present) | \(A = 2N\) |
| Equation 2 (Past, 2 yrs ago) | \(A-2 = 3(N-2)\) |
| Calculated Anita's Age (N) | 4 years |
| Calculated Asha's Age (A) | 8 years |
Age word problems are common in algebra and usually involve setting up and solving linear equations. Here’s a general approach:
Practice with different types of age problems will help you become more comfortable with setting up the correct equations.
Match List I with List II.
| List I | List II |
|---|---|
| (A) \( \frac{14 - (x - 1)}{10} = \frac{x + 5}{6} - 3 \) | (I) 4 |
| (B) \( (x - 5)^2 - (x + 3)^2 = 48 \) | (II) \( 23^2 \) |
| (C) \( 6(x - 4) = 4(x - 3) - 3(x - 8) \) | (III) 61 |
| (D) \( (2x - 1)(2x + 3) = (2x - 7)(2x + 7) \) | (IV) -2 |
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