Arrange the given quotients in ascending order.
1) 876.48 ÷ 83
2) 171.74 ÷ 62
3) 369.24 ÷ 17
2, 1, 3
To arrange the given quotients in ascending order, we need to calculate each quotient first:
- \(876.48 \div 83 = 10.56\)
- \(171.74 \div 62 = 2.77\)
- \(369.24 \div 17 = 21.72\)
Now, let's arrange the calculated quotients (10.56, 2.77, and 21.72) in ascending order:
2.77 < 10.56 < 21.72
This corresponds to the order 2, 1, 3.
Therefore, the correct ascending order of the quotients is 2, 1, 3.
Important Questions from Simplification
Simplify the following expression.
\(\left(\frac{7}{16} \div \frac{1}{2}\:of\: \frac{1}{5}\right)\times \frac{4}{5}-\frac{1}{3}\times\frac{5}{8}\div \frac{1}{2}+\frac{3}{4}\)
The value of \(\left( {2\frac{6}{7}of4\frac{1}{5} \div \frac{2}{3}} \right) \times 5\frac{1}{9} \div \left( {\frac{3}{4} \times 2\frac{2}{3}of\frac{1}{2} \div \frac{1}{4}} \right)\) is:
The value of \(\left[ {\frac{4}{7}\rm \;of\;2\frac{4}{5} \times 1\frac{2}{3} - \left( {3\frac{1}{2} - 2\frac{1}{6}} \right)} \right] \div \left( {3\frac{1}{5} \div 4\frac{1}{2}\;\rm of\;\;5\frac{1}{3}} \right)\) is:
The value of \(\frac{{0.0203 \times 2.92}}{{0.7 \times 0.0365 \times 2.9}} \div \frac{{{{\left( {12.12} \right)}^2} - {{\left( {8.12} \right)}^2}}}{{{{\left( {0.25} \right)}^2} + \left( {0.25} \right)\left( {19.99} \right)}}\) is:
The value of 4 ÷ 12 of [3 ÷ 4 of {(4 - 2) × 6 ÷ 2}] - 2 × 6 ÷ 8 + 3 is:
