Question
Arrange the following in chromatography process order :
A. Pack Column with Stationary phase
B. Inject Sample (Mobile Phase)
C. Partition/adsorption of analytes
D. Elution by mobile phase gradient
E. Detection and fraction collection
Choose the correct answer from the options given below :
The correct answer is
A, B, C, D, E
Chromatography Process Steps Explained
This question requires ordering the fundamental steps involved in a typical chromatography separation process.
Step-by-Step Order Determination
- A. Pack Column with Stationary phase: This is the initial preparation step where the column is filled with the stationary material.
- B. Inject Sample (Mobile Phase): After the column is prepared, the sample mixture is introduced onto the column, often dissolved or carried by the mobile phase.
- C. Partition/adsorption of analytes: Once the mobile phase starts flowing, the components (analytes) of the sample interact with the stationary and mobile phases through partitioning or adsorption. This is the basis of separation.
- D. Elution by mobile phase gradient: The mobile phase is passed through the column, potentially with changing composition (gradient), to carry the separated analytes off the column at different times.
- E. Detection and fraction collection: As the separated analytes exit the column, they are detected, and specific components can be collected in fractions.
Therefore, the correct sequence representing the chromatography process order is A, B, C, D, E.
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Important Questions from Miscellaneous
- Which of the following scheduler/schedulers is/are also called CPU scheduler ?
(A). Short Term Scheduler
(B). Long Term Scheduler
(C). Medium Term Scheduler
(D). Asymmetric Scheduler
Choose the correct answer from the options given below: - A situation where two or more processes are blocked, waiting for resources held by each other is called:
- External fragmentation occurs ________.
- Which disk scheduling algorithm looks for the track closest to the current head position?
- Which CPU scheduling algorithm prefers the process with the shortest burst time?
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