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Question

Arrange the following compounds in increasing order of their acid strength :

A. Propan - 1 - o1

B. 3 - nitrophenol

C. 3, 5 - dinitrophenol

D. Phenol

E. 4 - Methylphenol

Choose the correct answer from the options given below:

The correct answer is A < E < D < B < C

Understanding Acid Strength in Organic Compounds

The acid strength of a compound is determined by the stability of its conjugate base. A more stable conjugate base means the original acid is stronger. For alcohols and phenols, the conjugate base is formed by the loss of a proton (H⁺) from the hydroxyl (\(-\text{OH}\)) group, resulting in an alkoxide ion or a phenoxide ion, respectively.

Factors affecting the stability of the conjugate base:

  • Electronegativity: More electronegative atoms stabilize the negative charge better.
  • Resonance: Delocalization of the negative charge through resonance stabilizes the conjugate base. Phenols are more acidic than alcohols because the phenoxide ion is resonance-stabilized, while alkoxide ions are not.
  • Inductive Effects: Electron-withdrawing groups (like \(\text{NO}_2\)) attached to the carbon chain or ring near the acidic site pull electron density away, dispersing the negative charge and stabilizing the conjugate base, thus increasing acidity. Electron-donating groups (like \(\text{CH}_3\)) push electron density towards the negative charge, concentrating it and destabilizing the conjugate base, thus decreasing acidity.

Let's analyze the given compounds:

  1. A. Propan-1-ol: \(\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}\). This is an aliphatic alcohol. The conjugate base is a propoxide ion (\(\text{CH}_3\text{CH}_2\text{CH}_2\text{O}^-\)). There is no resonance stabilization. The alkyl group (\(\text{CH}_3\text{CH}_2\text{CH}_2-\)) is slightly electron-donating, destabilizing the negative charge.
  2. B. 3-nitrophenol: A phenol with a nitro group (\(-\text{NO}_2\)) at the meta position. The nitro group is strongly electron-withdrawing through inductive effects. While resonance is not significant at the meta position relative to the \(\text{OH}\) group, the strong inductive withdrawal stabilizes the 3-nitrophenoxide ion.
  3. C. 3,5-dinitrophenol: A phenol with two nitro groups (\(-\text{NO}_2\)) at the meta positions. The presence of two strongly electron-withdrawing nitro groups at meta positions exerts a significant inductive effect, highly stabilizing the 3,5-dinitrophenoxide ion. This compound is expected to be much more acidic than 3-nitrophenol.
  4. D. Phenol: The basic phenolic structure. The phenoxide ion is resonance-stabilized, making phenol more acidic than aliphatic alcohols.
  5. E. 4-Methylphenol: A phenol with a methyl group (\(-\text{CH}_3\)) at the para position. The methyl group is electron-donating primarily through hyperconjugation and a slight inductive effect. This destabilizes the 4-methylphenoxide ion compared to the plain phenoxide ion.

Comparing Acidity of Phenols vs Alcohols

Alcohols are generally much weaker acids than phenols. This is because the alkoxide ion (\(\text{R-O}^-\)) formed from an alcohol is not resonance-stabilized, whereas the phenoxide ion (\(\text{C}_6\text{H}_5\text{O}^-\)) formed from phenol is resonance-stabilized due to the delocalization of the negative charge into the aromatic ring. Thus, Propan-1-ol (A) will be the weakest acid among the given compounds.

Effect of Substituents on Phenol Acidity

For substituted phenols, electron-withdrawing groups increase acidity, while electron-donating groups decrease acidity compared to phenol itself.

  • Electron-Withdrawing Group (\(\text{NO}_2\)): The nitro group is strongly electron-withdrawing. In 3-nitrophenol (B), the \(\text{NO}_2\) group at the meta position primarily uses inductive withdrawal to stabilize the negative charge on the phenoxide oxygen. In 3,5-dinitrophenol (C), two \(\text{NO}_2\) groups provide even stronger inductive withdrawal, leading to greater stabilization of the conjugate base and thus higher acidity.
  • Electron-Donating Group (\(\text{CH}_3\)): The methyl group at the para position in 4-Methylphenol (E) is electron-donating through hyperconjugation and induction. This destabilizes the phenoxide ion by increasing electron density on the ring and oxygen, making 4-Methylphenol less acidic than phenol.

Ranking the Compounds by Acid Strength

Based on the analysis:

  1. Propan-1-ol (A) is an alcohol, making it the least acidic.
  2. Among the phenols, electron-donating groups decrease acidity, so 4-Methylphenol (E) is less acidic than unsubstituted Phenol (D). Thus, E < D.
  3. Electron-withdrawing groups increase acidity, so 3-nitrophenol (B) is more acidic than Phenol (D). Thus, D < B.
  4. More electron-withdrawing groups lead to higher acidity. 3,5-dinitrophenol (C) has two \(\text{NO}_2\) groups compared to one in 3-nitrophenol (B), making it the most acidic among these compounds. Thus, B < C.

Combining these comparisons, the increasing order of acid strength is:

Propan-1-ol (A) < 4-Methylphenol (E) < Phenol (D) < 3-nitrophenol (B) < 3,5-dinitrophenol (C)

This corresponds to the order A < E < D < B < C.

Compound Type / Substituent Effect on Acidity (compared to Phenol) Relative Acidity
A. Propan-1-ol Aliphatic Alcohol Much weaker acid than phenols (no resonance stabilization) Weakest
E. 4-Methylphenol Phenol with electron-donating \(\text{CH}_3\) (para) Decreases acidity (destabilizes phenoxide) Weaker than Phenol
D. Phenol Unsubstituted Phenol Reference point (resonance stabilized phenoxide) Baseline
B. 3-nitrophenol Phenol with electron-withdrawing \(\text{NO}_2\) (meta) Increases acidity (stabilizes phenoxide via induction) Stronger than Phenol
C. 3,5-dinitrophenol Phenol with two electron-withdrawing \(\text{NO}_2\) (meta) Greatly increases acidity (strong inductive stabilization) Strongest

Final Increasing Order of Acid Strength

Arranging them from weakest to strongest acid gives the order: A < E < D < B < C.

Revision Table: Acid Strength Comparison

Compound Structure Type Substituent Effect Summary Position in Order
Propan-1-ol (A) Aliphatic Alcohol No resonance stabilization of conjugate base. Weakest (1st)
4-Methylphenol (E) Substituted Phenol Electron-donating \(\text{CH}_3\) group destabilizes phenoxide. 2nd
Phenol (D) Unsubstituted Phenol Resonance stabilization of phenoxide ion. 3rd
3-nitrophenol (B) Substituted Phenol Electron-withdrawing \(\text{NO}_2\) group stabilizes phenoxide (primarily inductive). 4th
3,5-dinitrophenol (C) Substituted Phenol Two strong electron-withdrawing \(\text{NO}_2\) groups significantly stabilize phenoxide (inductive). Strongest (5th)

Additional Information on Acid Strength Factors

Beyond resonance and inductive effects, other factors influencing acidity include:

  • Electronegativity of the atom bearing the negative charge: Across a row in the periodic table, acidity increases as electronegativity increases (e.g., \(\text{CH}_4 < \text{NH}_3 < \text{H}_2\text{O} < \text{HF}\)).
  • Size of the atom bearing the negative charge: Down a group, acidity increases as atomic size increases, due to better dispersal of charge over a larger area (e.g., \(\text{HF} < \text{HCl} < \text{HBr} < \text{HI}\)).
  • Hybridization of the atom bearing the negative charge: Higher s-character of the orbital holding the negative charge leads to greater stability and higher acidity (e.g., alkynes > alkenes > alkanes).

In the context of substituted aromatic compounds like phenols, the position (ortho, meta, para) of the substituent also matters, particularly for groups that can exert resonance effects. While meta positions are primarily affected by inductive effects, ortho and para positions are affected by both inductive and resonance effects.

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Important Questions from Alcohols

  1. Butan-2-ol is a:

  2. The compound in which a hydroxy group, -OH, is attached to a saturated carbon atom which has two other carbon atoms attached to it is called:

  3. The reagent used for oxidation of trans-4-t-butylcyclohexanol to 4-t-butylcyclohexanone is _________.

  4. 1, 1- Diphenyl-2-propanone is reacted with compound a and b to form 1, 1-Diphenyl-2-propanol. a and b corresponds to ________.

  5. The reagent(s) used in hydroboration oxidation of propene are
    (A) $B_2H_6$
    (B) $H_2O$
    (C) $H_2O_2$
    (D) $OH^{-}$
    Choose the correct answer from the options given below:
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