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Question

Arrange products formed during payoff phase of the six-carbon glucose break down in correct sequence.
(A). 3-Phosphoglycerate
(B). Glyceraldehyde 3-phosphate
(C). Phosphoenolpyruvate
(D). 1,3-Bisphosphoglycerate
Choose the correct answer from the options given below:

The correct answer is
(B), (D), (A), (C).

Glucose Breakdown: Payoff Phase Sequence Explained

The payoff phase of glycolysis, also known as the energy payoff phase, is where the cell generates most of its ATP. This phase occurs after the initial 6-carbon glucose molecule has been split into two 3-carbon molecules. We will focus on the order in which the specific intermediates listed are formed.

Sequence of Products in Payoff Phase

The payoff phase begins with (B) Glyceraldehyde 3-phosphate. Here’s how the subsequent products are formed:

  1. (B) Glyceraldehyde 3-phosphate: This is the starting molecule for the payoff phase. It's a 3-carbon sugar phosphate derived from the earlier steps of glycolysis.
  2. (D) 1,3-Bisphosphoglycerate: Glyceraldehyde 3-phosphate is converted into 1,3-Bisphosphoglycerate. This step involves oxidation and the addition of a phosphate group, and it also produces NADH (a reduced electron carrier) from NAD$^+$.
  3. (A) 3-Phosphoglycerate: 1,3-Bisphosphoglycerate then donates a high-energy phosphate group to ADP, forming ATP through substrate-level phosphorylation. The molecule remaining is 3-Phosphoglycerate.
  4. (C) Phosphoenolpyruvate: 3-Phosphoglycerate is then transformed through a series of steps, eventually forming Phosphoenolpyruvate. This molecule also carries a high-energy phosphate bond, crucial for the next ATP generation.

The final step of glycolysis involves Phosphoenolpyruvate transferring its phosphate group to ADP, yielding pyruvate and another molecule of ATP.

Correct Sequence Identified

Based on the metabolic pathway, the intermediates appear in the following chronological sequence:

(B) Glyceraldehyde 3-phosphate is converted to (D) 1,3-Bisphosphoglycerate, which is then converted to (A) 3-Phosphoglycerate. Finally, (A) 3-Phosphoglycerate is converted to (C) Phosphoenolpyruvate.

Therefore, the correct sequence is (B), (D), (A), (C).

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Important Questions from Miscellaneous

  1. Which of the following scheduler/schedulers is/are also called CPU scheduler ?
    (A). Short Term Scheduler
    (B). Long Term Scheduler
    (C). Medium Term Scheduler
    (D). Asymmetric Scheduler
    Choose the correct answer from the options given below:
  2. A situation where two or more processes are blocked, waiting for resources held by each other is called:
  3. External fragmentation occurs ________.
  4. Which disk scheduling algorithm looks for the track closest to the current head position?
  5. Which CPU scheduling algorithm prefers the process with the shortest burst time?
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