Analogy between momentum and heat transfer is known as
Chilton-Colburn analogy
The question asks for the specific analogy that relates momentum transfer to heat transfer. In fluid mechanics and heat transfer studies, analogies are used to simplify complex relationships between different transport phenomena, such as momentum, heat, and mass transfer. These analogies allow engineers to predict one type of transfer based on measurements or correlations for another.
The Chilton-Colburn analogy is a well-established relationship that effectively connects the rate of momentum transfer (related to skin friction) with the rate of heat transfer (related to convective heat transfer coefficients) in turbulent flow regimes.
This analogy is often expressed using dimensionless parameters. The Chilton-Colburn analogy specifically states that the Colburn j-factor ($j_H$), which represents heat transfer, is equal to half of the friction factor ($f$), which represents momentum transfer, corrected by the Prandtl number raised to the power of two-thirds:
$$j_H = \frac{h_c}{c_p G} \text{Pr}^{2/3} = \frac{f}{2}$$
Where:
This equation shows a direct correlation between heat transfer characteristics ($j_H$) and momentum transfer characteristics ($f$), making it the correct answer for the analogy between momentum and heat transfer.
While other analogies exist (like the Reynolds analogy, which is a simpler form often valid for gases where Pr ≈ 1), the Chilton-Colburn analogy provides a more generalized relationship that accounts for fluids with Prandtl numbers different from unity. It is specifically known for linking the friction factor (momentum) to the heat transfer j-factor.
The Stanton-Prandtl analogy is related but often refers to broader correlations or the Reynolds analogy itself. The Grassoff-Meyer analogy is not typically associated with the direct comparison of momentum and heat transfer in this context.
Therefore, the most accurate and widely recognized analogy fitting the description is the Chilton-Colburn analogy.
An ic engine has a bore and a stroke length of 4 cm each. The total surface area through which heat transfer takes place in cm2 is.
Which of the following is not the regimes of pool boiling?
Nucleate boiling regime is formed approximately between
[ΔTexcess = excess temperature]For flow through a pipe of radius R, the velocity and temperature distribution are as follows:
\(u\left( {r,x} \right) = {C_1},and\ T\left( {r,x} \right) = {C_2}{\left[{1 - (\frac{r}{R})^3} \right]}\), where C1 and C2 are constants. The bulk mean temperature is given by \({T_m} = \frac{2}{{{u_m}{R^2}}}\mathop \smallint \limits_0^R u\left( {r,x} \right)T\left( {r,x} \right)rdr,\)
with Um being the mean velocity of flow. The value of Tm is
The unit of overall heat transfer coefficient is