(Rounded off to two decimal places)
The question asks for "water depth (in metres per metre depth of soil)", which is equivalent to the volumetric water content ($\theta_v$). This represents the volume of water present in a unit volume of soil.
The given dimensions of the core cylinder are used to determine the total volume of the soil sample.
The calculation involves finding the volume of water and the total volume of the soil sample.
$W_w = W_m - W_d$
$W_w = 0.48\text{ kg} - 0.44\text{ kg} = 0.04\text{ kg}$
$V_w = \frac{W_w}{\rho_w}$
$V_w = \frac{0.04\text{ kg}}{1000\text{ kg.m}^{-3}} = 0.00004\text{ m}^3$
$V_{soil} = \pi r^2 L$
$V_{soil} = \pi \times (0.030\text{ m})^2 \times (0.100\text{ m})$
$V_{soil} = \pi \times 0.0009\text{ m}^2 \times 0.100\text{ m}$
$V_{soil} = \pi \times 0.00009\text{ m}^3 \approx 0.000282743\text{ m}^3$
$\theta_v = \frac{V_w}{V_{soil}}$
$\theta_v = \frac{0.00004\text{ m}^3}{0.000282743\text{ m}^3} \approx 0.141421$
$\theta_v \approx 0.14$
The calculated value of 0.14 is within the provided correct answer range of 0.12 to 0.16.
Undisturbed soil sample is collected from a field when the soil moisture is at field capacity. The inside diameter of the core sampler is 7.5 cm with a height of 15 cm. Weight of the core sampling cylinder with moist soil is 2.81 kg and that with oven dry soil is 2.61 kg. The weight of the core sampling cylinder is 1.56 kg. Assuming $\pi = 3.14$, the water depth in centimeter per meter depth of soil (rounded off to two decimal places) is__________.
| Column-I | Column-II |
| 1) Neutron Probe | P) Open channel flow |
| 2) Pressure Plate Apparatus | Q) Deep percolation |
| 3) Tipping Bucket | R) Aquifer parameters |
| 4) Current Meter | S) Soil moisture |
| 5) Pumping Test | T) Rainfall intensity |
| 6) Lysimeter | U) Soil-moisture characteristic curve |