An observer 2 m tall is 150\(\sqrt3\) m away from a tower. The angle of elevation from his eye to the top of the tower is 60°. The height of the tower is:
452 m
This problem involves using trigonometry, specifically the concept of the angle of elevation, to find the height of a tower given the height of an observer, the distance from the observer to the tower, and the angle of elevation from the observer's eye to the top of the tower.
We can visualize this scenario as a right-angled triangle. The base of the triangle is the distance from the observer to the tower. The perpendicular side is the height difference between the observer's eye level and the top of the tower. The angle of elevation is formed at the observer's eye, looking up towards the top of the tower.
Let the total height of the tower be \(H\) meters. Since the angle of elevation is taken from the observer's eye level, we first need to find the height from the observer's eye level to the top of the tower. Let this height be \(h\) meters.
In the right-angled triangle formed:
The trigonometric ratio relating the opposite and adjacent sides is the tangent function.
$$ \tan(\text{angle of elevation}) = \frac{\text{Opposite side}}{\text{Adjacent side}} $$
Substituting the given values:
$$ \tan(60\degree) = \frac{h}{150\sqrt{3}} $$
We know that the value of \(\tan(60\degree)\) is \(\sqrt{3}\).
$$ \sqrt{3} = \frac{h}{150\sqrt{3}} $$
To find \(h\), we multiply both sides of the equation by \(150\sqrt{3}\):
$$ h = \sqrt{3} \times 150\sqrt{3} $$
$$ h = 150 \times (\sqrt{3})^2 $$
$$ h = 150 \times 3 $$
$$ h = 450 \text{ m} $$
So, the height from the observer's eye level to the top of the tower is 450 m.
The total height of the tower is the sum of the height from the ground to the observer's eye level (which is the observer's height) and the height from the observer's eye level to the top of the tower (\(h\)).
Total height of tower \(H\) = Observer's height + \(h\)
$$ H = 2 \text{ m} + 450 \text{ m} $$
$$ H = 452 \text{ m} $$
Therefore, the height of the tower is 452 meters.
| Description | Value | Calculation/Reason |
|---|---|---|
| Observer's Height | 2 m | Given |
| Distance to Tower | \(150\sqrt{3}\) m | Given (Adjacent side) |
| Angle of Elevation | 60° | Given |
| Height from eye level to top (\(h\)) | 450 m | \(\tan(60\degree) = h / (150\sqrt{3})\) > \(h = \sqrt{3} \times 150\sqrt{3} = 450\) |
| Total Height of Tower | 452 m | Observer's Height + \(h = 2 + 450\) |
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