All Exams Test series for 1 year @ ₹349 only
Question

An objective function Z = ax + by is maximum at points (8, 2) and (4, 6). If a ≥ 0, b ≥ 0, and ab = 25, then the maximum value of the function is:

The correct answer is

50

Understanding the Problem: Linear Programming and Objective Functions

The question involves a concept from Linear Programming, specifically dealing with an objective function $Z = ax + by$ that is being maximized. We are given that the maximum value of this function occurs at two distinct points, (8, 2) and (4, 6), within the feasible region. We are also given constraints on the coefficients $a$ and $b$: $a \ge 0$, $b \ge 0$, and $ab = 25$. Our goal is to find the maximum value of the function $Z$.

Key Concept: Maximum at Multiple Points in Linear Programming

In Linear Programming, if an objective function attains its maximum (or minimum) value at two distinct corner points of the feasible region, then it attains the same maximum (or minimum) value at every point on the line segment connecting these two corner points. This occurs when the objective function line is parallel to the line segment connecting the two points.

This means the slope of the objective function line $ax + by = Z_{max}$ must be equal to the slope of the line segment connecting the points (8, 2) and (4, 6).

Calculating the Slope of the Line Segment

The slope of a line segment connecting two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula:

$\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}$

Using the points (8, 2) and (4, 6):

$(x_1, y_1) = (8, 2)$

$(x_2, y_2) = (4, 6)$

$\text{Slope of segment} = \frac{6 - 2}{4 - 8} = \frac{4}{-4} = -1$

Determining the Relationship between 'a' and 'b'

The objective function is $Z = ax + by$. To find the slope of the objective function line $ax + by = Z$, we can rearrange it into slope-intercept form ($y = mx + c$):

$by = -ax + Z$

$y = -\frac{a}{b}x + \frac{Z}{b}$

The slope of the objective function line is $-\frac{a}{b}$.

Since the objective function is maximum at all points on the segment connecting (8, 2) and (4, 6), its slope must equal the slope of this segment:

$-\frac{a}{b} = -1$

This simplifies to:

$\frac{a}{b} = 1$

$a = b$

Finding the Values of 'a' and 'b'

We are given the condition $ab = 25$. We have also found that $a = b$. Substitute $a$ for $b$ in the equation $ab = 25$:

$a \cdot a = 25$

$a^2 = 25$

Taking the square root of both sides:

$a = \pm \sqrt{25}$

$a = \pm 5$

We are given the constraint $a \ge 0$. Therefore, we must choose the positive value:

$a = 5$

Since $a = b$, we also have:

$b = 5$

These values ($a=5, b=5$) satisfy the conditions $a \ge 0$, $b \ge 0$, and $ab = 5 \times 5 = 25$.

Calculating the Maximum Value of the Objective Function

Now that we have the values of $a$ and $b$, the objective function is $Z = 5x + 5y$.

To find the maximum value, we can evaluate $Z$ at either of the given points where the maximum occurs, (8, 2) or (4, 6).

Evaluating at point (8, 2):

$Z = 5(8) + 5(2)$

$Z = 40 + 10$

$Z = 50$

Evaluating at point (4, 6):

$Z = 5(4) + 5(6)$

$Z = 20 + 30$

$Z = 50$

Both points yield the same maximum value.

Point (x, y)Objective Function $Z = 5x + 5y$Value of Z
(8, 2)$5(8) + 5(2)$50
(4, 6)$5(4) + 5(6)$50


 

The maximum value of the function is 50.

Revision Table: Key Steps to Solve Linear Programming Problem

StepDescriptionAction Taken
1Identify given informationObjective function $Z=ax+by$, max at (8,2) and (4,6), $a \ge 0, b \ge 0, ab=25$.
2Understand implication of max at two pointsSlope of objective function line equals slope of line segment connecting the points.
3Calculate slope of segment$\frac{6-2}{4-8} = -1$.
4Relate objective function slope to segment slope$-\frac{a}{b} = -1 \implies a = b$.
5Use constraint to find a and b$ab=25$ and $a=b \implies a^2=25$. With $a \ge 0$, $a=5$, so $b=5$.
6Formulate specific objective function$Z = 5x + 5y$.
7Calculate max valueEvaluate $Z$ at (8, 2) or (4, 6). $Z = 5(8) + 5(2) = 50$.


 

Additional Information: Linear Programming Fundamentals

Linear Programming (LP) is a mathematical method for determining a way to achieve the best outcome (such as maximum profit or lowest cost) in a mathematical model whose requirements are represented by linear relationships. Key components include:

  • Objective Function: A linear function ($Z = ax + by$) that you want to maximize or minimize. The coefficients 'a' and 'b' represent the per-unit contribution of variables 'x' and 'y' to the objective.
  • Decision Variables: The variables (like 'x' and 'y' here) whose values you need to determine to achieve the optimal solution.
  • Constraints: A set of linear inequalities or equations that the decision variables must satisfy. These define the feasible region. In this problem, the constraints defining the feasible region are not explicitly given, but the points (8, 2) and (4, 6) are stated to be points where the maximum occurs, implying they are likely corner points of the feasible region. Also, $a \ge 0$ and $b \ge 0$ can be considered constraints on the parameters.
  • Feasible Region: The set of all possible points $(x, y)$ that satisfy all the constraints. This region is always a convex polygon in 2D.
  • Corner Points (Vertices): The vertices of the feasible region. The optimal solution (maximum or minimum) of a linear objective function always occurs at one of these corner points. If it occurs at two adjacent corner points, it occurs at all points on the edge connecting them.

This problem highlights the property that if optimality occurs at two vertices, the objective function's contour line at the optimal value is parallel to the edge connecting these vertices.

 

Was this answer helpful?

Important Questions from Linear Programming

  1. If \[ \begin{bmatrix} 5x + 8 & 7 \\ y + 3 & 10x + 12 \end{bmatrix} = \begin{bmatrix} 2 & 3y + 1 \\ 5 & 0 \end{bmatrix} \] then the value of \( 5x + 3y \) is equal to:

  2. The least non-negative remainder when \( 3^{51} \) is divided by 7 is:

  3. The corner points of the feasible region for an L.P.P. are (0, 10), (5, 5), (5, 15) and (0, 30). If the objective function is Z = αx + βy, α, β > 0, the condition on α and β so that the maximum of Z occurs at corner points (5, 5) and (0, 20) is :

  4. In a 700 m race, Amit reaches the finish point in 20 seconds and Rahul reaches in 25 seconds. Amit beats Rahul by a distance of :

  5. A person wants to invest an amount of ₹ 75,000. He has two options A and B yielding 8% and 9% return respectively on the invested amount. He plans to invest at least ₹15,000 in Plan A and at least ₹25,000 in Plan B. Also he wants that his investment in Plan A is less than or equal to his investment in Plan B. Which of the following options describes the given LPP to maximize the return (where x and y are investments in Plan A and Plan B respectively)?

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App