An LVDT is used to measure displacement. The LVDT feeds a voltmeter of 0-5 V range through a 250 gain amplifier. For a displacement of 0.5 mm, the output of LVDT is 2 mV. The sensitivity of the instrument is
1 V/mm
An LVDT (Linear Variable Differential Transformer) is a widely used sensor for measuring linear displacement. This problem requires us to calculate the sensitivity of an LVDT system, which includes an amplifier and a voltmeter.
To find the sensitivity, we first need to identify all the provided parameters:
The sensitivity of an instrument is generally defined as the ratio of the change in output signal to the change in the input quantity it is measuring.
The first step is to determine the final output voltage that the voltmeter will display after the signal has been amplified. The LVDT's raw output needs to be converted from millivolts (mV) to Volts (V) for calculations.
Raw LVDT Output = $2 \text{ mV}$
Converting millivolts to Volts:
Raw LVDT Output = $2 \times 10^{-3} \text{ V}$
Now, we apply the amplifier's gain to this raw output:
Amplified Output Voltage = Raw LVDT Output $\times$ Amplifier Gain
Amplified Output Voltage = $(2 \times 10^{-3} \text{ V}) \times 250$
Amplified Output Voltage = $0.5 \text{ V}$
So, the voltmeter will read 0.5 V for a displacement of 0.5 mm.
With the amplified output voltage calculated, we can now determine the overall sensitivity of the instrument system.
Sensitivity = $\frac{\text{Amplified Output Voltage}}{\text{Displacement}}$
Plugging in the values we have:
Sensitivity = $\frac{0.5 \text{ V}}{0.5 \text{ mm}}$
Sensitivity = $1 \text{ V/mm}$
The calculated sensitivity for the instrument is 1 V/mm. This means that for every millimeter of displacement measured by the LVDT, the amplified output voltage increases by 1 Volt. This value matches one of the provided options.
The options given were:
Our calculated sensitivity of 1 V/mm corresponds to the third option.
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