An iron ball at 60°C is dropped in a mug containing water at 60°C. The heat will
Not flow from iron ball to water or from water to iron ball.
Heat is a form of energy that transfers from one object to another due to a temperature difference. The direction of heat flow is always from a region of higher temperature to a region of lower temperature.
Consider two objects, object A and object B. If object A is at a higher temperature than object B, heat will flow from A to B. If object B is at a higher temperature than object A, heat will flow from B to A.
What happens when two objects are at the same temperature? When two objects are at the same temperature, they are said to be in thermal equilibrium. In thermal equilibrium, there is no net flow of heat energy between the objects. Although energy transfer might still occur at a microscopic level, the rate of energy transfer in one direction is equal to the rate of energy transfer in the opposite direction, resulting in no overall change in temperature or internal energy.
In this question, we have an iron ball and water. We are given the temperature of both:
Since the temperature of the iron ball is exactly the same as the temperature of the water (60\(^\circ\)C = 60\(^\circ\)C), there is no temperature difference between them. According to the principle of heat flow, heat transfer occurs only when there is a temperature difference.
Because the iron ball and the water are already at the same temperature, they are in a state of thermal equilibrium as soon as the ball is dropped into the water. Therefore, there will be no net heat flow either from the iron ball to the water or from the water to the iron ball.
Let's look at the given options based on our understanding:
Based on the principle of heat transfer and thermal equilibrium, when the iron ball at 60\(^\circ\)C is dropped into water at 60\(^\circ\)C, there will be no net flow of heat between them.
The process by which heat is transferred from the hotter end to the colder end of an object is known as ______.
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