This problem involves finding the sum of an infinite geometric series. The volumes of the boxes form a sequence where each term is half of the previous one.
The formula for the sum (S) of an infinite geometric series is:
$ S = \frac{a}{1-r} $
This formula is valid only if the absolute value of the common ratio is less than 1 (i.e., $|r| < 1$). In this case, $|1/2| < 1$, so the formula can be applied.
Substitute the values of a and r into the formula:
$ S = \frac{20}{1 - \frac{1}{2}} $
First, calculate the denominator:
$ 1 - \frac{1}{2} = \frac{1}{2} $
Now, perform the division:
$ S = \frac{20}{\frac{1}{2}} = 20 \times 2 = 40 $
The total volume of all the boxes is $40\text{ cc}$.