This problem involves finding the sum of an infinite geometric series. The volumes of the boxes form a sequence where each term is half of the previous one.
The formula for the sum (S) of an infinite geometric series is:
$ S = \frac{a}{1-r} $
This formula is valid only if the absolute value of the common ratio is less than 1 (i.e., $|r| < 1$). In this case, $|1/2| < 1$, so the formula can be applied.
Substitute the values of a and r into the formula:
$ S = \frac{20}{1 - \frac{1}{2}} $
First, calculate the denominator:
$ 1 - \frac{1}{2} = \frac{1}{2} $
Now, perform the division:
$ S = \frac{20}{\frac{1}{2}} = 20 \times 2 = 40 $
The total volume of all the boxes is $40\text{ cc}$.
If a, b and c are in Geometric Progression and $a^\frac{1}{x} = b^\frac{1}{y} = c^\frac{1}{z}$ then, x, y, z are in ________.
Which of the following statement is true about the geometric series
$ 1 + r +r^2 + r^3 + ...............; (r > 0) $?
$6240$ रुपये की राशि $30$ किस्तों में इस प्रकार चुकाई जाती है कि प्रत्येक किस्त पिछली किस्त से $10$ रुपये अधिक है । पहली किस्त की मूल्य ____________है।