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Question

An ideal gas is compressed in a cylinder by a movable piston to a volume one-half its original volume. During this process it was found that 320 kJ of the heat was rejected by the gas and internal energy of the gas remained the same. What was the amount of work done on the gas?

The correct answer is

320 kJ

Taking heat into the gas and work done on it as positive, \(\Delta U=Q+W_{\mathrm{on}}\). Thus \(W_{\mathrm{on}}=\Delta U-Q=0-(-320)=320\ \mathrm{kJ}\).

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Important Questions from First Law of Thermodynamics

  1. Heat transfer in a cyclic process are +20 kJ, -5 kJ, -10 kJ and +15kJ. Net work done for this cycle will be given by:

  2. An open system is one in which ______.

  3. A system will be in thermodynamic equilibrium only if it is in ____.

    A. Thermal equilibrium

    B. Mechanical equilibrium

    C. Chemical equilibrium

  4. The gas constant (R) is equal to the _____ of two specific heats.

  5. In a reversible adiabatic process the ration \(\left( {\frac{{{T_1}}}{{{T_2}}}} \right)\) is equal to:

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