An even number is the determinant of which of the following matrices? (A) \(\begin{bmatrix} 1 & -1 \\ -1 & 5 \end{bmatrix}\) (B) \(\begin{bmatrix} 13 & -1 \\ -1 & 15 \end{bmatrix}\) (C) \(\begin{bmatrix} 16 & -1 \\ -11 & 15 \end{bmatrix}\) (D) \(\begin{bmatrix} 6 & -12 \\ 11 & 15 \end{bmatrix}\) Choose the correct answer from the options given below:
(A), (B) and (D) only
The question asks us to identify which of the given 2x2 matrices have a determinant that is an even number. To solve this, we need to calculate the determinant for each matrix provided in the options and then determine if the calculated value is even or odd.
For a 2x2 matrix given by \( \begin{bmatrix} a & b \\ c & d \end{bmatrix} \), the determinant is calculated using the formula:
\( \text{Determinant} = ad - bc \)
We will apply this formula to each matrix.
The first matrix is \( \begin{bmatrix} 1 & -1 \\ -1 & 5 \end{bmatrix} \). Here, \(a=1\), \(b=-1\), \(c=-1\), and \(d=5\).
Determinant of (A) = \((1 \times 5) - (-1 \times -1)\)
= \(5 - (1)\)
= \(5 - 1\)
= \(4\)
The determinant is 4. Since 4 is divisible by 2, it is an even number.
The second matrix is \( \begin{bmatrix} 13 & -1 \\ -1 & 15 \end{bmatrix} \). Here, \(a=13\), \(b=-1\), \(c=-1\), and \(d=15\).
Determinant of (B) = \((13 \times 15) - (-1 \times -1)\)
= \(195 - (1)\)
= \(195 - 1\)
= \(194\)
The determinant is 194. Since 194 is divisible by 2 (\(194 = 2 \times 97\)), it is an even number.
The third matrix is \( \begin{bmatrix} 16 & -1 \\ -11 & 15 \end{bmatrix} \). Here, \(a=16\), \(b=-1\), \(c=-11\), and \(d=15\).
Determinant of (C) = \((16 \times 15) - (-1 \times -11)\)
= \(240 - (11)\)
= \(240 - 11\)
= \(229\)
The determinant is 229. Since 229 is not divisible by 2, it is an odd number.
The fourth matrix is \( \begin{bmatrix} 6 & -12 \\ 11 & 15 \end{bmatrix} \). Here, \(a=6\), \(b=-12\), \(c=11\), and \(d=15\).
Determinant of (D) = \((6 \times 15) - (-12 \times 11)\)
= \(90 - (-132)\)
= \(90 + 132\)
= \(222\)
The determinant is 222. Since 222 is divisible by 2 (\(222 = 2 \times 111\)), it is an even number.
Let's summarize the results for each matrix:
| Matrix | Determinant Value | Parity (Even/Odd) |
|---|---|---|
| (A) | 4 | Even |
| (B) | 194 | Even |
| (C) | 229 | Odd |
| (D) | 222 | Even |
Based on our calculations, the matrices with an even determinant are (A), (B), and (D).
The matrices (A), (B), and (D) have even determinants. Therefore, the correct option should list (A), (B), and (D).
| Concept | Description | 2x2 Formula |
|---|---|---|
| Determinant | A scalar value computed from the elements of a square matrix. It provides important information about the matrix, such as invertibility. | For \( \begin{bmatrix} a & b \\ c & d \end{bmatrix} \), determinant is \(ad - bc\) |
| Even Number | An integer that is exactly divisible by 2. | Examples: -4, 0, 2, 4, 194, 222 |
| Odd Number | An integer that is not exactly divisible by 2. | Examples: -3, -1, 1, 3, 5, 229 |
Determinants are fundamental in linear algebra and have several key properties:
Understanding how to calculate determinants is crucial for solving systems of linear equations (using Cramer's rule), finding eigenvalues, and performing other matrix operations.
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Given the determinant:
\[ \Delta = \begin{vmatrix} 1 & \cos x & 1 \\ -\cos x & 1 & \cos x \\ -1 & -\cos x & 1 \end{vmatrix} \]
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(B) \( \Delta = 2(2 - \sin^2 x) \)
(C) Minimum value of \( \Delta \) is 2
(D) Maximum value of \( \Delta \) is 4
Choose the correct answer from the options given below: