(where the symbols have their usual meanings)
The question asks for the speed of an electromagnetic wave as it travels through a linear homogeneous medium. We need to relate this speed to the speed of light in a vacuum and the properties of the medium.
We want to express the speed v in the medium in terms of c and the properties of the vacuum and the medium. We start with the formula for v:
$$v = \frac{1}{\sqrt{\varepsilon \mu}}$$To introduce c, we can multiply and divide by $ \sqrt{\varepsilon_0 \mu_0} $:
$$v = \frac{1}{\sqrt{\varepsilon \mu}} \times \frac{\sqrt{\varepsilon_0 \mu_0}}{\sqrt{\varepsilon_0 \mu_0}}$$Rearranging the terms, we get:
$$v = \left( \frac{1}{\sqrt{\varepsilon_0 \mu_0}} \right) \times \left( \frac{\sqrt{\varepsilon_0 \mu_0}}{\sqrt{\varepsilon \mu}} \right)$$Recognizing that $ \frac{1}{\sqrt{\varepsilon_0 \mu_0}} $ is the speed of light in vacuum, c, we can substitute it:
$$v = c \times \sqrt{\frac{\varepsilon_0 \mu_0}{\varepsilon \mu}}$$Let's compare our derived formula, $ v = c \sqrt{\frac{\varepsilon_0 \mu_0}{\varepsilon \mu}} $, with the given options:
The speed of an electromagnetic wave in a linear homogeneous medium is correctly given by the formula derived from the fundamental constants and the medium's properties.
$$v = c \sqrt{\frac{\varepsilon_0 \mu_0}{\varepsilon \mu}}$$This expression shows how the speed is reduced from its vacuum value c due to the presence of the medium's permittivity $ \varepsilon $ and permeability $ \mu $.