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Question

An electric heater draws a current of 10 A when connected to 220 V output terminal. Its resistance is

The correct answer is

22 Ω

Understanding the Electric Heater Problem

The question asks us to find the resistance of an electric heater. We are given the voltage at which the heater is connected and the amount of current it draws. This is a classic problem that can be solved using Ohm's Law, which relates voltage, current, and resistance in an electrical circuit.

Applying Ohm's Law to Find Electric Heater Resistance

Ohm's Law states that the voltage (V) across a conductor is directly proportional to the current (I) flowing through it, provided the temperature and other physical conditions remain constant. The constant of proportionality is the resistance (R) of the conductor.

The formula derived from Ohm's Law is:

\begin{equation*} V = I \times R \end{equation*}

Where:

  • \(V\) is the Voltage (measured in Volts, V)
  • \(I\) is the Current (measured in Amperes, A)
  • \(R\) is the Resistance (measured in Ohms, Ω)

To find the resistance of the electric heater, we need to rearrange this formula to solve for R:

\begin{equation*} R = \frac{V}{I} \end{equation*}

This formula allows us to calculate the electrical resistance calculation of the heater using the given voltage and current values.

Calculation Steps for Electric Heater Resistance

We are given the following information for the electric heater:

  • Voltage, \(V = 220\) V
  • Current, \(I = 10\) A

We want to find the resistance, \(R\).

Using the rearranged Ohm's Law formula, \(R = \frac{V}{I}\), we substitute the given values:

\begin{equation*} R = \frac{220 \text{ V}}{10 \text{ A}} \end{equation*}

Now, we perform the division:

\begin{equation*} R = 22 \text{ } \Omega \end{equation*}

So, the resistance of the electric heater is 22 Ω. This electrical resistance calculation is a direct application of Ohm's Law. Understanding Ohm's Law is key to solving problems involving electric heater resistance and other electrical components.

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Important Questions from Current, Resistance and Electricity

  1. What is the relation between Volt(V) and Joule (J)?

  2. Potential Difference is

  3. The alternating current cannot be used for

  4. If a current of 18.2 Ampere per second flows through a copper conductor and the average collision time of electrons is 0.25 μs, then the value of conductivity of the copper conductor is ______.

  5. Consider a copper cylinder at room temperature. What happens to the resistivity of a copper cylinder as its temperature increases?

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