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Question

An aquifer of sand has a saturated column of cross - sectional area 0.2 $\times$ 5 m and a depth of 3 m. If the specific yield of sand is 25% , how much water can be extracted from the aquifer ?

The correct answer is
0.75 m$^3$

Aquifer Water Extraction Calculation

This solution details the calculation for determining the amount of water extractable from a saturated sand aquifer based on its dimensions and specific yield.

Determine Aquifer Volume

First, calculate the total volume of the saturated portion of the aquifer.

  1. Calculate the cross-sectional area:

    Area = Width $\times$ Length = $0.2 \, \text{m} \times 5 \, \text{m} = 1.0 \, \text{m}^2$

  2. Calculate the total saturated volume:

    Volume = Area $\times$ Depth = $1.0 \, \text{m}^2 \times 3 \, \text{m} = 3.0 \, \text{m}^3$

Calculate Extractable Water

Next, use the specific yield to find the volume of water that can be extracted.

  1. Convert the specific yield percentage to a decimal:

    Specific Yield ($S_y$) = 25% = 0.25

  2. Calculate the extractable water volume:

    Extractable Water = Total Volume $\times S_y$

    Extractable Water = $3.0 \, \text{m}^3 \times 0.25 = 0.75 \, \text{m}^3$

Therefore, 0.75 cubic meters of water can be extracted from the aquifer.

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Important Questions from Distribution of Water - Teaching

  1. Global average water consumption (L/person/day) is :
  2. Ground water occurs under :

     (a) Unconfined condition in shallow aquifers 

    (b) Semi Confined aquifers

     (c) Confined aquifers 

    Choose the correct answer :

  3. Which of the following methods is the most effective for conserving water?

  4. The method of analysis of distribution system in which domestic supply is neglected and fire demand is considered is:

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