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Question

An angle was measured with a standard error of 5". How many observations a surveyor needs to take in order to obtain a standard error of 1" for the mean value of this angle?

The correct answer is
25

Angle Measurement Observations Calculation

To find the required number of observations ($n$) for a desired standard error of the mean ($SE_M$), we use the relationship between the standard error of a single measurement ($SE$) and the number of observations.

Standard Error Formula

The formula connecting these values is:

$SE_M = \frac{SE}{\sqrt{n}}$

Calculating Required Observations

We are given:

  • Standard error of a single measurement, $SE = 5''$.
  • Desired standard error of the mean, $SE_M = 1''$.

We need to find the number of observations, $n$.

Step 1: Rearrange the formula to solve for $n$.

From $SE_M = \frac{SE}{\sqrt{n}}$, we get:

$\sqrt{n} = \frac{SE}{SE_M}$

Step 2: Square both sides to find $n$.

$n = \left(\frac{SE}{SE_M}\right)^2$

Step 3: Substitute the given values.

$n = \left(\frac{5''}{1''}\right)^2$

Step 4: Calculate the result.

$n = (5)^2$

$n = 25$

Therefore, 25 observations are needed to obtain a standard error of 1'' for the mean value of the angle.

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Important Questions from Errors in Observations

  1. The carrier phase observation model in GNSS is given as $$ \phi_A^i = f \delta^i - \frac{\rho_A^i}{\lambda} - f \delta_A + N_A^i - f \delta_{\text{iono}} + f \delta_{\text{tropo}} + \epsilon $$ where $\phi_A^i$ is the observed carrier phase in cycles, $f$ is the frequency of the carrier in hertz, and $\lambda$ is the wavelength of the carrier in meters.

    What is the unit of the ionospheric ($\delta_{\text{iono}}$) and tropospheric ($\delta_{\text{tropo}}$) delay terms in the given equation?

  2. In GNSS positioning, the cycle slips are the most detrimental for estimating _______.
  3. According to the first order ionospheric delay term, the time delay experienced by the GNSS signal is directly proportional to the Total Electron Content (TEC) in the ionosphere, and inversely proportional to the square of the frequency of the carrier wave. Based on this, the GPS L2 (1227.60 MHz) carrier is slower than the GPS L1 (1575.42 MHz) carrier by a factor of ________ for a given TEC (Rounded off to the nearest integer).
  4. In the context of Global Navigation Satellite System positioning, the Saastamoinen model provides a correction for ________.
  5. In the choke ring antenna there are concentric cylinders placed around the antenna that are of a certain depth to minimize the multipath effect. If the signal wavelength is $\lambda$, then the depth of the cylinders in the choke ring antenna should be
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