[Given: First law of thermodynamics $dU= dQ+dW$]
$dW= -pdV, dQ=0$
We need to determine the change in the internal energy of an air parcel undergoing compression, given the First Law of Thermodynamics and specific conditions.
The First Law of Thermodynamics states:
$dU = dQ + dW$
Where:
The problem provides two key conditions:
Substituting $dQ = 0$ into the First Law gives:
$dU = dW$
Substituting the expression for $dW$ gives:
$dU = -pdV$
The process is described as 'compression', meaning the volume of the air parcel decreases.
Now, let's calculate the sign of $dU$:
$dU = -p \times dV$
$dU = -(positive) \times (negative)$
$dU = positive$
Since $dU$ is positive, the internal energy of the air parcel increases during compression when no heat is exchanged.
The internal energy will increase.
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