An air parcel having initial temperature of 15°C rises adiabatically to 2 km height above the surface. What is the final temperature of the parcel?
An air parcel rising adiabatically cools due to expansion. This calculation uses the Dry Adiabatic Lapse Rate (DALR), approximately $9.8 ^\circ C$ per kilometer, representing the temperature decrease with altitude.
Given Initial Temperature ($T_1$): $15^\circ C$.
Using the conversion formula $T(\text{K}) = T(^\circ C) + 273.15$:
$ T_1 = 15 + 273.15 = 288.15 \text{ K} $
Altitude Gain ($\Delta z$): $2$ km.
Dry Adiabatic Lapse Rate (DALR): $9.8 ^\circ C/\text{km}$.
Temperature Decrease ($\Delta T$) = DALR $\times \Delta z$:
$ \Delta T = 9.8 ^\circ C/\text{km} \times 2 \text{ km} = 19.6 ^\circ C $
Final Temperature ($T_2$) in Kelvin:
$ T_2 (\text{K}) = T_1 (\text{K}) - \Delta T $
$ T_2 = 288.15 \text{ K} - 19.6 ^\circ C = 268.55 \text{ K} $
Using the conversion formula $T(^\circ C) = T(\text{K}) - 273.15$:
$ T_2 (^\circ C) = 268.55 \text{ K} - 273.15 $
$ T_2 = -4.6 ^\circ C $
The final temperature of the air parcel is approximately $ -4.6 ^\circ C $. This corresponds to Option C.
Consider the following salient features of Tornado and choose the correct option:
A. Tornadoes are very violent rotating systems of air
B. The pressure in the center of tornado is extremely low
C. The movement of tornadoes is in well-defined route and direction
D. The arrival of tornado is heralded by dark and thick clouds in the sky
Choose the correct answer from the options given below :