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Question

Amongst the following, which one is the most appropriate strategy to sequence and assemble highly repeated regions of a genome?

The correct answer is

Sequencing of BAC libraries

Sequencing Highly Repeated Genome Regions

Sequencing and assembling a genome can be challenging, especially when dealing with regions that are highly repetitive. Highly repeated regions are sequences of DNA that appear multiple times throughout the genome. When using sequencing methods that produce short reads, these reads can map to multiple locations in the genome, making it difficult to determine their original position and correctly assemble the sequence.

Let's consider the options provided:

  • Shotgun sequencing: This method involves breaking the entire genome into many small fragments, sequencing these fragments (reads), and then using computer algorithms to assemble the genome by finding overlapping reads. While effective for much of the genome, the short reads generated can cause significant problems in highly repeated regions, leading to gaps or misassemblies because identical reads from different repeat copies cannot be easily distinguished.
  • Illumina sequencing: A popular high-throughput sequencing technology that produces very short reads (typically 50-300 base pairs). Like standard shotgun sequencing, its short read length makes it particularly challenging to span or resolve highly repeated DNA sequences, which can be much longer than the read length.
  • 454 sequencing: An older sequencing technology that produced longer reads (up to 1000 base pairs) compared to early Illumina, but shorter than Sanger sequencing. While longer reads can help slightly more than very short reads in spanning small repeats, highly repeated regions, especially long ones, still pose significant assembly difficulties for this technology when used alone on whole-genome fragments.
  • Sequencing of BAC libraries: BAC stands for Bacterial Artificial Chromosome. BAC libraries are created by cloning large fragments of genomic DNA (typically 100-300 kilobases) into bacterial plasmids. By sequencing individual BAC clones, which contain much larger pieces of the genome than the reads from shotgun, Illumina, or 454 methods, it becomes possible to span and resolve complex highly repeated regions. A single BAC clone might contain an entire repeat sequence or the unique sequences flanking it, allowing for its assembly independently. These assembled BAC sequences can then be used as scaffolds or anchors to help assemble the entire genome, providing a framework that correctly positions the highly repeated regions. This strategy is particularly useful for genomes with high repeat content, like many plant genomes.

Therefore, among the given options, sequencing of BAC libraries is considered the most appropriate strategy specifically for sequencing and assembling highly repeated regions of a genome because the large clone sizes help overcome the limitations imposed by short sequencing reads in navigating repetitive landscapes.

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Important Questions from Molecular Biology Techniques

  1. Which one of the following does NOT use RNA-sequencing?

  2. Which one of the following statements related to molecular cloning procedures is INCORRECT?

  3. Given below are statements related to various molecular techniques

    A. During molecular cloning of DNA fragments, a vector and insert molecule digested with two different enzymes can never be ligated with each other.

    B. Only 3' → 5' exonucleases and not 5' → 3' exonucleases can be used for digesting nucleic acids to generate blunt-ended fragments for cloning.

    C. In Sanger's dideoxy sequencing method, each reaction consists of a mixture of three dNTPs and one ddNTP.

    D. Self-ligation of a vector with compatible ends can be prevented by treatment with alkaline phosphatase.

    Which one of the following options represents a combination of correct statements?

  4. Given below are four DNA sequences and a set of forward and reverse primers for PCR amplification.

    SequencePrimes
    A 5' ACAATCGT.....ACTAGTAC-3'FP: 5'-TGTTAG-3'
    RP: 5'-TAGTAC-3'
    B5' AGTCTTAG.....ATGCCAGT - 3'FP: 5'-AAGACT-3'
    RP: 5'-ACTGGC-3'
    C5' CTTGACTA.....GTACAGTCA-3'FP: 5'-CTTGAC-3'
    RP: 5'-TGACTG-3'
    DD 5' GATCTAGC.....TCAAGCAGAC-3'FP: 5'-GATCTA-3'
    RP: 5'-CAGACG-3'
    In the absence of any other factors such as (but not restricted to) Tm, length, percent GC, etc., which one of the above template-primers combinations would produce an amplified fragment?
  5. Which one of the following statements is TRUE?

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