The question asks for the speed of a boat in still water. We are given a relationship between the boat's downstream and upstream speeds and the speed of the river current.
Let $S_b$ represent the speed of the boat in still water and $S_w$ represent the speed of the river current.
We are given $S_w = 8$ kmph.
The problem states that the downstream speed is thrice the upstream speed:
$S_d = 3 \times S_u$
Substitute the expressions for $S_d$ and $S_u$:
$S_b + S_w = 3 \times (S_b - S_w)$
Now, substitute the value of the river flow speed, $S_w = 8$ kmph:
$S_b + 8 = 3 \times (S_b - 8)$
Expand the equation:
$S_b + 8 = 3S_b - 24$
Rearrange the terms to solve for $S_b$:
$8 + 24 = 3S_b - S_b$
$32 = 2S_b$
Calculate the speed of the boat in still water:
$S_b = \frac{32}{2}$
$S_b = 16 \text{ kmph}$