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Question

According to VSEPR theory, what is the shape of the $ClF_3$ molecule?

The correct answer is T-shape

Understanding Molecular Shape with VSEPR Theory: The Case of $ClF_3$

The Valence Shell Electron Pair Repulsion (VSEPR) theory is a model used in chemistry to predict the geometry of individual molecules based on the number of electron pairs surrounding their central atoms. It operates on the principle that electron pairs (both bonding and non-bonding/lone pairs) repel each other and will arrange themselves around the central atom to be as far apart as possible, minimizing this repulsion. This arrangement determines the molecule's shape.

Applying VSEPR Theory to Chlorine Trifluoride ($ClF_3$)

Let's determine the molecular shape of $ClF_3$ step-by-step:

Step 1: Identify the Central Atom

In the $ClF_3$ molecule, Chlorine (Cl) is the central atom as it is less electronegative than Fluorine (F).

Step 2: Calculate Total Valence Electrons

We sum the valence electrons from all atoms:

  • Chlorine (Cl) is in Group 17, contributing 7 valence electrons.
  • Fluorine (F) is also in Group 17, each contributing 7 valence electrons. Since there are three Fluorine atoms, they contribute $3 \times 7 = 21$ valence electrons.
  • Total valence electrons = $7 (\text{from Cl}) + 21 (\text{from 3 F atoms}) = 28$ valence electrons.

Step 3: Determine Electron Pairs Around the Central Atom

Next, we distribute these electrons to form bonds and lone pairs around the central Chlorine atom:

  • Chlorine forms single bonds with each of the three Fluorine atoms. This uses $3 \times 2 = 6$ electrons.
  • Each Fluorine atom requires 6 electrons (3 lone pairs) to complete its octet. This uses $3 \times 6 = 18$ electrons.
  • Electrons used so far = $6 (\text{bonds}) + 18 (\text{F lone pairs}) = 24$ electrons.
  • Remaining electrons = Total valence electrons - Electrons used = $28 - 24 = 4$ electrons.
  • These remaining 4 electrons form lone pairs on the central Chlorine atom. Number of lone pairs = $4 / 2 = 2$ lone pairs.

Step 4: Determine the Steric Number and Electron Geometry

The steric number is the sum of the number of atoms bonded to the central atom and the number of lone pairs on the central atom.

  • Number of bonded atoms (F) = 3
  • Number of lone pairs on Cl = 2
  • Steric Number = $3 + 2 = 5$.

A steric number of 5 corresponds to a **trigonal bipyramidal** electron geometry. This means the 5 electron domains (3 bonding pairs and 2 lone pairs) arrange themselves in a trigonal bipyramidal fashion around the central Cl atom.

Step 5: Determine the Molecular Geometry

The molecular geometry describes the arrangement of only the atoms, not the lone pairs. In a trigonal bipyramidal electron geometry, lone pairs occupy positions that minimize repulsion. Lone pairs prefer equatorial positions over axial positions.

  • The two lone pairs on Chlorine will occupy two of the equatorial positions in the trigonal bipyramid.
  • The three Fluorine atoms will occupy the remaining one equatorial position and the two axial positions.

This arrangement of atoms leads to a molecular shape known as **T-shape**. The three Fluorine atoms are positioned roughly like the points of a 'T', with the Chlorine atom at the intersection, and the lone pairs extending outwards from the equatorial plane.

Summary Table

Component Count Geometry Contribution
Bonded Atoms (F) 3 Affects molecular shape
Lone Pairs (on Cl) 2 Affects molecular shape and bond angles
Steric Number 5 Determines electron geometry (Trigonal Bipyramidal)
Molecular Shape - T-shape

Therefore, based on VSEPR theory, the molecular shape of $ClF_3$ is T-shaped.

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Important Questions from Chemical Bonding and Molecular Structure

  1. Which of the following elements possesses the property of catenation?

  2. Which of the following intermolecular is also called as London force?

  3. The oxygen molecule is paramagnetic. It can be explained by

  4. The geometry in accordance with VSEPR theory in \(CIF_4^+\) is __________.

  5. Even if fluorine is more electronegative than hydrogen, resultant dipole of NH3 is greater than that of NF3. This is due to ___________.

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