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Question

AB is parallel to CD. A transversal PQ intersects AB and CD at E and F, respectively, and $\angle$PEB = 49°. G is a point between AB and CD such that $\angle$BEG = 35° and $\angle$GFE = 16°. What is the measure of $\angle$EGF?

The correct answer is
68°

Geometry Angles: Parallel Lines and Transversal Problems

This problem involves finding an unknown angle ($\angle EGF$) given information about parallel lines, a transversal, and other angles.

Understanding Parallel Lines and Transversals

Key concepts used:

  • When a transversal intersects two parallel lines, alternate interior angles are equal.
  • Vertically opposite angles are equal.
  • Angles on a straight line add up to 180°.
  • The sum of the angles in a triangle is always 180°.

Step-by-Step Calculation for Angle EGF

We are given:

  • Line AB is parallel to line CD ($AB \parallel CD$).
  • PQ is a transversal intersecting AB at E and CD at F.
  • $\angle PEB = 49^\circ$.
  • G is a point between AB and CD.
  • $\angle BEG = 35^\circ$.
  • $\angle GFE = 16^\circ$.

Let's find the measure of $\angle EGF$:

  1. Find $\angle AEF$: The angle $\angle AEF$ is vertically opposite to $\angle PEB$. Therefore, $\angle AEF = \angle PEB = 49^\circ$.
  2. Find $\angle BEF$: Angles $\angle AEF$ and $\angle BEF$ form a linear pair along the straight line AB. Thus, $\angle BEF + \angle AEF = 180^\circ$.
    $\angle BEF = 180^\circ - \angle AEF$
    $\angle BEF = 180^\circ - 49^\circ = 131^\circ$.
  3. Find $\angle FEG$: We are given $\angle BEG = 35^\circ$. Since G is a point between the parallel lines AB and CD, the ray EG must lie within the angle $\angle BEF$. Therefore, we can write $\angle BEF$ as the sum of $\angle BEG$ and $\angle FEG$.
    $\angle BEF = \angle BEG + \angle FEG$
    $131^\circ = 35^\circ + \angle FEG$
    $\angle FEG = 131^\circ - 35^\circ = 96^\circ$.
  4. Find $\angle EGF$ using triangle EFG: Now consider the triangle $\triangle EFG$. The sum of angles in a triangle is $180^\circ$. We know $\angle EFG$ and $\angle FEG$.
    $\angle EGF + \angle FEG + \angle EFG = 180^\circ$
    We have $\angle EFG = 16^\circ$ (given) and $\angle FEG = 96^\circ$ (calculated).
    $\angle EGF + 96^\circ + 16^\circ = 180^\circ$
    $\angle EGF + 112^\circ = 180^\circ$
    $\angle EGF = 180^\circ - 112^\circ$
    $\angle EGF = 68^\circ$.

Conclusion

The measure of angle $\angle EGF$ is $68^\circ$. This result is obtained by applying the properties of angles formed by parallel lines and transversals, specifically vertically opposite angles and angles on a straight line, and finally using the angle sum property of a triangle.

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Important Questions from Geometry

  1. The sides of a triangle are in the ratio 6 : 4 : 3 and its perimeter is 104 cm. The length of the longest side (in cm) is:

  2. An isosceles right-angled triangle has hypotenuse length as 10 units. What is the area of the triangle (in square units)?

  3. Two circles of radii 16 cm and 4 cm, respectively, touch each other externally at Point A. PQ is the direct common tangent of these circles with centres C1 and C2, respectively. What is the length of PQ?

  4. Let C be a circle with center O and AB be a chord of C such that the length of AB is equal to the radius of C. Let D be any point on the major arc of AB. Find ∠AOB and ∠ADB, respectively.

  5. The centres of two circles are 84 cm apart. If the radii of these two circles are 38 cm and 26 cm, respectively, then which of the following options gives the length (in cm) of a direct common tangent of these two circles?

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