All Exams Test series for 1 year @ ₹349 only
Question

AB is parallel to CD. A transversal PQ intersects AB and CD at E and F, respectively, and $\angle$PEB = 49°. G is a point between AB and CD such that $\angle$BEG = 35° and $\angle$GFE = 16°. What is the measure of $\angle$EGF?

The correct answer is
68°

Geometry Angles: Parallel Lines and Transversal Problems

This problem involves finding an unknown angle ($\angle EGF$) given information about parallel lines, a transversal, and other angles.

Understanding Parallel Lines and Transversals

Key concepts used:

  • When a transversal intersects two parallel lines, alternate interior angles are equal.
  • Vertically opposite angles are equal.
  • Angles on a straight line add up to 180°.
  • The sum of the angles in a triangle is always 180°.

Step-by-Step Calculation for Angle EGF

We are given:

  • Line AB is parallel to line CD ($AB \parallel CD$).
  • PQ is a transversal intersecting AB at E and CD at F.
  • $\angle PEB = 49^\circ$.
  • G is a point between AB and CD.
  • $\angle BEG = 35^\circ$.
  • $\angle GFE = 16^\circ$.

Let's find the measure of $\angle EGF$:

  1. Find $\angle AEF$: The angle $\angle AEF$ is vertically opposite to $\angle PEB$. Therefore, $\angle AEF = \angle PEB = 49^\circ$.
  2. Find $\angle BEF$: Angles $\angle AEF$ and $\angle BEF$ form a linear pair along the straight line AB. Thus, $\angle BEF + \angle AEF = 180^\circ$.
    $\angle BEF = 180^\circ - \angle AEF$
    $\angle BEF = 180^\circ - 49^\circ = 131^\circ$.
  3. Find $\angle FEG$: We are given $\angle BEG = 35^\circ$. Since G is a point between the parallel lines AB and CD, the ray EG must lie within the angle $\angle BEF$. Therefore, we can write $\angle BEF$ as the sum of $\angle BEG$ and $\angle FEG$.
    $\angle BEF = \angle BEG + \angle FEG$
    $131^\circ = 35^\circ + \angle FEG$
    $\angle FEG = 131^\circ - 35^\circ = 96^\circ$.
  4. Find $\angle EGF$ using triangle EFG: Now consider the triangle $\triangle EFG$. The sum of angles in a triangle is $180^\circ$. We know $\angle EFG$ and $\angle FEG$.
    $\angle EGF + \angle FEG + \angle EFG = 180^\circ$
    We have $\angle EFG = 16^\circ$ (given) and $\angle FEG = 96^\circ$ (calculated).
    $\angle EGF + 96^\circ + 16^\circ = 180^\circ$
    $\angle EGF + 112^\circ = 180^\circ$
    $\angle EGF = 180^\circ - 112^\circ$
    $\angle EGF = 68^\circ$.

Conclusion

The measure of angle $\angle EGF$ is $68^\circ$. This result is obtained by applying the properties of angles formed by parallel lines and transversals, specifically vertically opposite angles and angles on a straight line, and finally using the angle sum property of a triangle.

Was this answer helpful?

Important Questions from Geometry

  1. ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?

  2. If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:

  3. If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.  

  4. If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?

  5. D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App