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Question

A yellow-colored complex P upon addition of aqueous HNO3 forms a very pale violet-colored complex Q. Complex Q on reaction with NaCl forms a yellow-colored complex R. The species P, Q and R, respectively, that are consistent with the above observations, are

The correct answer is

P = [Fe(H2O)5(OH)2+; Q = [Fe(H2O)6]3+ and R = [Fe(H2O)5(Cl)]2+

Identifying Complex P, Q, and R

The question asks us to identify three iron complexes, P, Q, and R, based on their colors and reactions with specific reagents. We are given the color of P (yellow), the color of Q (pale violet), and the color of R (yellow), along with the reactions that transform P into Q and Q into R.

Complex P: The Starting Yellow Complex

Complex P is described as yellow. We need to look at the options and see which complex is likely to be yellow. The first option suggests P is \( \text{[Fe(H}_2\text{O)}_5\text{(OH)]}^{2+} \). Iron(III) hydrolysis products, like \( \text{[Fe(H}_2\text{O)}_5\text{(OH)]}^{2+} \), are often yellow or brownish in aqueous solution due to charge transfer transitions.

Reaction 1: P to Q upon addition of HNO₃

Complex P reacts with aqueous HNO₃ (an acid) to form a very pale violet-colored complex Q. Let's consider the proposed structure of P from option 1, \( \text{[Fe(H}_2\text{O)}_5\text{(OH)]}^{2+} \). This complex contains a hydroxide ligand \( \text{(OH)}^- \). Adding an acid \( \text{(H}^+ \text{ from HNO}_3\text{)} \) will protonate the hydroxide ligand, turning it into a water molecule \( \text{(H}_2\text{O)} \).

The reaction would be:

\( \text{[Fe(H}_2\text{O)}_5\text{(OH)]}^{2+}\text{(aq)} \) \( + \text{ H}^+\text{(aq)} \) \( \longrightarrow \) \( \text{[Fe(H}_2\text{O)}_6\text{]}^{3+}\text{(aq)} \)
(Complex P) (from HNO₃) (Complex Q)

The proposed complex Q in option 1 is \( \text{[Fe(H}_2\text{O)}_6\text{]}^{3+} \). This reaction transforms the \( \text{[Fe(H}_2\text{O)}_5\text{(OH)]}^{2+} \) complex into the hexaaquairon(III) ion, \( \text{[Fe(H}_2\text{O)}_6\text{]}^{3+} \). The hexaaquairon(III) ion is typically pale violet or almost colorless in dilute solutions. This matches the observed color change from yellow (P) to pale violet (Q).

Reaction 2: Q to R upon reaction with NaCl

Complex Q reacts with NaCl to form a yellow-colored complex R. NaCl provides chloride ions \( \text{(Cl)}^- \). Complex Q is \( \text{[Fe(H}_2\text{O)}_6\text{]}^{3+} \). Chloride ions are known to be ligands that can displace water molecules in coordination complexes.

The reaction would be a ligand substitution:

\( \text{[Fe(H}_2\text{O)}_6\text{]}^{3+}\text{(aq)} \) \( + \text{ Cl}^-\text{(aq)} \) \( \longrightarrow \) \( \text{[Fe(H}_2\text{O)}_5\text{(Cl)]}^{2+}\text{(aq)} \) \( + \text{ H}_2\text{O(l)} \)
(Complex Q) (from NaCl)   (Complex R)  

The proposed complex R in option 1 is \( \text{[Fe(H}_2\text{O)}_5\text{(Cl)]}^{2+} \). Chloro complexes of iron(III), like \( \text{[Fe(H}_2\text{O)}_5\text{(Cl)]}^{2+} \) or even \( \text{[FeCl}_4\text{]}^- \), are typically yellow. This matches the observed color change from pale violet (Q) back to yellow (R).

Summary of Species P, Q, and R

Based on the reactions and color changes described in the question, the species P, Q, and R consistent with the observations are:

  • P: \( \text{[Fe(H}_2\text{O)}_5\text{(OH)]}^{2+} \) (yellow)
  • Q: \( \text{[Fe(H}_2\text{O)}_6\text{]}^{3+} \) (pale violet)
  • R: \( \text{[Fe(H}_2\text{O)}_5\text{(Cl)]}^{2+} \) (yellow)

These species and their transformations align perfectly with the reactions and colors given in the problem statement.

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Important Questions from p - Block

  1. The correct statement for alkali metal is:
  2. Consider the following pairs of compounds.

    (i) NH4Cl and FeO

    (ii) H3N∙BF3 and BCl3

    (iii) HSO3F and HF

    The more acidic species in (i), (ii) and (iii) are, respectively

  3. Which of the following has the lowest boiling point?

  4. Choose the equilibria from the following that are NOT favoured to go to right:

    (A) As2S5 + 5HgO ⇌ As2O5 + 5 HgS

    (B) La2(CO3)3 + Bi2S3 ⇌ La2S3 + Bi2(CO3)3

    (C) CdSO4 + CaS ⇌ CdS + CaSO4

    (D) BeF2 + HgI2 ⇌ BeI2 + HgF2

  5. The reaction of XeF6 with a limited amount of quartz gives compound A. Then on reaction with an equivalent amount of XeO3, A gives B. The products A and B are, respectively

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