A window is made up of a square portion and an equilateral triangle portion above it. The base of the triangular portion coincides with the upper side of the square. If the perimeter of the window is 6 m, the area of the window in m2 is ___________.
2.06
This problem asks us to find the total area of a unique window design. The window is made up of two distinct geometric shapes: a square portion and an equilateral triangle portion placed on top of it. We are given the total perimeter of this window, which is 6 meters, and our goal is to calculate its area in square meters.
Let's first visualize and understand the structure of the window:
To find the area, we first need to determine the side length of the square and the triangle. Let's denote this common side length as \(s\) meters.
The perimeter of the window is the total length of its outer boundary. Let's count how many sides of length \(s\) contribute to the perimeter:
Therefore, the total perimeter \(P\) of the window is the sum of these external sides:
\[P = (\text{number of square sides in perimeter} \times s) + (\text{number of triangle sides in perimeter} \times s)\]
\[P = (3 \times s) + (2 \times s)\]
\[P = 3s + 2s\]
\[P = 5s\]
We are given that the perimeter of the window is 6 meters:
\[5s = 6 \text{ m}\]
Now, we can solve for \(s\):
\[s = \frac{6}{5} \text{ m}\]
\[s = 1.2 \text{ m}\]
So, the side length of the square and each side of the equilateral triangle is 1.2 meters.
Now that we know the side length \(s = 1.2\) m, we can calculate the area of the square portion and the area of the equilateral triangle portion separately.
The formula for the area of a square is \( \text{side} \times \text{side} \), or \( \text{side}^2 \).
\[\text{Area}_{\text{square}} = s^2\]
Substitute \(s = 1.2\) m into the formula:
\[\text{Area}_{\text{square}} = (1.2 \text{ m})^2\]
\[\text{Area}_{\text{square}} = 1.44 \text{ m}^2\]
The formula for the area of an equilateral triangle with side length \(s\) is:
\[\text{Area}_{\text{triangle}} = \frac{\sqrt{3}}{4} s^2\]
Substitute \(s = 1.2\) m into the formula:
\[\text{Area}_{\text{triangle}} = \frac{\sqrt{3}}{4} (1.2 \text{ m})^2\]
\[\text{Area}_{\text{triangle}} = \frac{\sqrt{3}}{4} (1.44 \text{ m}^2)\]
Using the approximate value of \( \sqrt{3} \approx 1.732 \):
\[\text{Area}_{\text{triangle}} \approx \frac{1.732}{4} \times 1.44 \text{ m}^2\]
\[\text{Area}_{\text{triangle}} \approx 0.433 \times 1.44 \text{ m}^2\]
\[\text{Area}_{\text{triangle}} \approx 0.62352 \text{ m}^2\]
To find the total area of the window, we add the area of the square portion and the area of the equilateral triangle portion:
\[\text{Total Area}_{\text{window}} = \text{Area}_{\text{square}} + \text{Area}_{\text{triangle}}\]
\[\text{Total Area}_{\text{window}} = 1.44 \text{ m}^2 + 0.62352 \text{ m}^2\]
\[\text{Total Area}_{\text{window}} = 2.06352 \text{ m}^2\]
Rounding this value to two decimal places, we get approximately 2.06 m\(^2\).
| Description | Value |
|---|---|
| Given Perimeter of Window | 6 m |
| Perimeter Formula (\(P = 5s\)) | \(5s = 6\) |
| Calculated Side Length (\(s\)) | 1.2 m |
| Area of Square (\(s^2\)) | \( (1.2)^2 = 1.44 \text{ m}^2 \) |
| Area of Equilateral Triangle (\(\frac{\sqrt{3}}{4}s^2\)) | \( \frac{\sqrt{3}}{4}(1.2)^2 \approx 0.62352 \text{ m}^2 \) |
| Total Area of Window | \( 1.44 + 0.62352 \approx 2.06352 \text{ m}^2 \) |
The area of the window is approximately 2.06 m\(^2\).
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