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Question

A wastewater is expected to have $BOD_{3}^{27}$ of about 300 mg/L. The initial DO of dilution water is 8.5 mg/L. The minimum DO that should remain is 1.5 mg/L. The dilution requirement for BOD determination is :

The correct answer is
50 times dilution of the sample

Wastewater BOD Dilution Calculation

The dilution factor ($DF$) required for a Biochemical Oxygen Demand (BOD) test is calculated to ensure that the dissolved oxygen (DO) level in the diluted sample remains sufficient for the microorganisms to function and for accurate measurement after the incubation period.

Formula for Dilution Factor

The calculation is based on the initial DO, the minimum required DO, the sample's BOD concentration, and the dilution factor itself. The relationship is derived from the oxygen available for consumption:

Oxygen Available for Consumption = Initial DO - Minimum Remaining DO

This available oxygen must be greater than or equal to the oxygen consumed by the diluted sample ($BOD_s / DF$).

$ DO_{initial} - DO_{minimum} \ge \frac{BOD_s}{DF} $

Rearranging the formula to find the minimum required dilution factor:

$ DF \ge \frac{BOD_s}{DO_{initial} - DO_{minimum}} $

Applying the Values

Given:

  • BOD of the sample ($BOD_s$) = 300 mg/L
  • Initial DO of dilution water ($DO_{initial}$) = 8.5 mg/L
  • Minimum DO that should remain ($DO_{minimum}$) = 1.5 mg/L

Substitute these values into the formula:

$ DF \ge \frac{300 \text{ mg/L}}{8.5 \text{ mg/L} - 1.5 \text{ mg/L}} $

$ DF \ge \frac{300 \text{ mg/L}}{7 \text{ mg/L}} $

$ DF \ge 42.857 $

Determining the Correct Dilution

The dilution factor must be at least 42.857. We need to choose the option that meets this requirement.

  • Option 1: 100 times dilution (Meets requirement)
  • Option 2: 50 times dilution (Meets requirement)
  • Option 3: 200 times dilution (Meets requirement)
  • Option 4: 150 times dilution (Meets requirement)

In BOD testing, the goal is to achieve the lowest possible dilution factor that still satisfies the DO requirement, as excessive dilution can introduce errors. Among the options provided, 50 is the smallest dilution factor that is greater than 42.857.

Therefore, a 50 times dilution is appropriate.

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Important Questions from Quality and Characteristics of Sewage

  1. Conventionally, the biochemical oxygen demand (BOD) is measured for _______ days.

  2. Consider the following statements:

    1. Ammonia nitrogen is a measure of nitrogen present as ammonium hydroxide and ammonium salts. It will progressively decrease as sewage gets treated.

    2. Organic nitrogen is the total nitrogenous matter in sewages excepting that present as ammonia nitrogen, nitrites and nitrates. It becomes ammonia in anaerobic decomposition and nitrites or nitrates in aerobic decomposition.

    Which of the above statements is/are correct?
  3. Identify the correct relation from the following:

    Where BOD, COD, and TOD are Biochemical, Chemical, and Theoretical oxygen demand, respectively.

  4. What is the correct range of \(\frac{{BO{D_u}}}{{COD}}\) for a waste water to be considered as fully biodegradable?

    (where BODu = ultimate Bio-chemical oxygen  demand and COD = chemical oxygen demand)

  5. Determine ultimate BOD for sewage having 5-day BOD at 20°C as 180 ppm. Assume the de-oxygenation constant as 0.8 per day.

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