A vehicle suspension system consists of a leaf spring and a damper. The stiffness of the leaf spring is 3.6 kN/m and damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor and damped natural frequency respectively are
0.471 and 1.19 Hz
This solution details the process of calculating the damping factor and the damped natural frequency for a given vehicle suspension system. We will use the provided values for mass, stiffness, and damping constant.
The vehicle suspension system is modeled as a mass-spring-damper system. The essential components and their properties are:
| Parameter | Symbol | Value | Unit |
|---|---|---|---|
| Mass | $m$ | 50 | kg |
| Stiffness (Leaf Spring) | $k$ | 3.6 | kN/m |
| Damping Constant (Damper) | $c$ | 400 | Ns/m |
It is important to convert the stiffness value to standard SI units (N/m) for calculations: $k = 3.6 \, \text{kN/m} = 3600 \, \text{N/m}$.
The core calculations rely on fundamental concepts in vibration analysis:
We will now compute the required values step-by-step:
Using the mass ($m = 50$ kg) and stiffness ($k = 3600$ N/m):
$$ \omega_n = \sqrt{\frac{3600 \, \text{N/m}}{50 \, \text{kg}}} $$ $$ \omega_n = \sqrt{72 \, \text{s}^{-2}} $$ $$ \omega_n \approx 8.485 \, \text{rad/s} $$First, determine the critical damping coefficient ($c_c$):
$$ c_c = 2\sqrt{mk} = 2\sqrt{50 \, \text{kg} \times 3600 \, \text{N/m}} $$ $$ c_c = 2\sqrt{180000 \, \text{kg}^2/\text{s}^2} $$ $$ c_c = 2 \times 424.26 \, \text{kg/s} $$ $$ c_c \approx 848.53 \, \text{Ns/m} $$Next, use the given damping constant ($c = 400$ Ns/m) to calculate the damping factor ($\zeta$):
$$ \zeta = \frac{c}{c_c} = \frac{400 \, \text{Ns/m}}{848.53 \, \text{Ns/m}} $$ $$ \zeta \approx 0.4714 $$Calculate the damped angular frequency ($\omega_d$) using the previously found $\omega_n$ and $\zeta$:
$$ \omega_d = \omega_n \sqrt{1 - \zeta^2} $$ $$ \omega_d = 8.485 \, \text{rad/s} \times \sqrt{1 - (0.4714)^2} $$ $$ \omega_d = 8.485 \, \text{rad/s} \times \sqrt{1 - 0.2222} $$ $$ \omega_d = 8.485 \, \text{rad/s} \times \sqrt{0.7778} $$ $$ \omega_d = 8.485 \, \text{rad/s} \times 0.8819 $$ $$ \omega_d \approx 7.482 \, \text{rad/s} $$Finally, convert the damped angular frequency ($\omega_d$) to the damped natural frequency ($f_d$) in Hertz:
$$ f_d = \frac{\omega_d}{2\pi} = \frac{7.482 \, \text{rad/s}}{2\pi \, \text{rad}} $$ $$ f_d \approx \frac{7.482}{6.283} $$ $$ f_d \approx 1.191 \, \text{Hz} $$The calculated values for the vehicle suspension system are:
These results closely match the values presented in the first option.
______ is defined as the ratio of the actual damping coefficient to a critical damping coefficient.
A spring-mass-damper system having single degree of freedom has a spring with strength 25 kN/m, mass 0.1 kg and coefficient of damping 40 N-s/m. The damping factor of the system will be
The damping ratio for a viscously damped spring mass system, governed by the relationship is \(m\frac{{{d^2}x}}{{d{t^2}}} + c\frac{{dx}}{{dt}} + kx = F\) given by