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Question

A vehicle is travelling with a speed of 100 kmph on a level surface, what is the lag distance travelled during reaction time of the driver considering coefficient of friction is 0.35 and reaction time of the driver is 2.5 sec?

The correct answer is

69.5 m

Understanding the distance a vehicle covers during a driver's reaction time is crucial in road safety calculations. This distance is known as the lag distance.

Understanding Lag Distance

Lag distance is the distance a vehicle travels from the moment the driver detects a situation requiring a stop or change in speed to the moment the brakes are actually applied. During this time, the vehicle continues to move at its initial speed because no deceleration has started yet. It depends only on the initial speed of the vehicle and the driver's reaction time.

The question provides us with the following information:

  • Speed of the vehicle (V) = 100 kmph
  • Reaction time of the driver (t) = 2.5 seconds
  • Coefficient of friction (f) = 0.35 (Note: This value is relevant for calculating braking distance, but not for lag distance. The question specifically asks for lag distance during reaction time).

Calculating Lag Distance from Speed and Reaction Time

To calculate the lag distance, we need to use the formula:

Lag Distance = Speed $\times$ Reaction Time

First, the speed needs to be converted from kilometers per hour (kmph) to meters per second (m/s) to be consistent with the reaction time unit (seconds).

Conversion from kmph to m/s:

1 km = 1000 meters

1 hour = 3600 seconds

So, $100 \text{ kmph} = 100 \times \frac{1000 \text{ m}}{3600 \text{ s}}$

$100 \text{ kmph} = \frac{100000}{3600} \text{ m/s} = \frac{1000}{36} \text{ m/s} = \frac{250}{9} \text{ m/s}$

Step-by-Step Lag Distance Calculation

Now, we can calculate the lag distance using the converted speed and the given reaction time:

Speed (V) = $\frac{250}{9}$ m/s

Reaction time (t) = 2.5 s

Lag Distance = V $\times$ t

Lag Distance = $\frac{250}{9} \text{ m/s} \times 2.5 \text{ s}$

Lag Distance = $\frac{250}{9} \times \frac{5}{2} \text{ m}$

Lag Distance = $\frac{1250}{18} \text{ m}$

Lag Distance = $\frac{625}{9} \text{ m}$

Calculating the numerical value:

Lag Distance $\approx 69.44$ meters

Comparing with Options

The calculated lag distance is approximately 69.44 meters. Let's compare this with the given options:

  • Option 1: 59.5 m
  • Option 2: 49.5 m
  • Option 3: 69.5 m
  • Option 4: 79.5 m

The value 69.44 m is closest to 69.5 m.

Conclusion

The lag distance travelled by the vehicle during the driver's reaction time of 2.5 seconds, while travelling at a speed of 100 kmph, is approximately 69.5 meters.

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Important Questions from Highway Geometric Design

  1. The rate of super-elevation for a horizontal curve of radius $500 \text{ m}$ in a national highway for a design speed of $65 \text{ kmph}$ is:

  2. Consider the following statements about grade compensation:

    (i) Grade compensation is given up to the maximum value of '75/R', where R is the radius of circular curve in metres.

    (ii) According to Indian Roads Congress, grade compensation is not necessary for gradients flatter than 4 percent.

    Which of the above statement/s is/are correct?

  3. The type of transition curve that is generally provided on hill road is

  4. The minimum design speed adopted where hair-pin bends are provided at hill roads is _________.

  5. The rear wheels do not follow the same path as that of the front wheels. This phenomenon is called:

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